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1 year ago

If the angle of incidence of light falling on a plane mirror is 30Â°, what will be the angle of reflection?.

1 answer:

7 0

The angle of reflection made when the angle of incidence of light falling on a plane mirror is 30 degrees is 30 degrees (made with a surface normal to the mirror surface.) The reflected ray will make an angle of (90- 30=) 60 degrees with the mirror surface.

It is referred to as light reflection when a light ray hits a polished or smooth surface and bounces back. The incident light rays hit the surface and are reflected off of it. The beam that returns is referred to as the reflected ray.

The angle of reflection and the angle of incidence, are the angles formed by these light rays when they reflect back or fall on a surface, respectively.

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Irina finds an unlabeled box of fine needles, and wants to determine how thick they are. A standard ruler will not do the job, a

Vsevolod [243]

Answer:

$d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m$

Explanation:

The expression which represent the first diffraction minima by a circular aperture is given by $d sin\Theta =1.22\lambda$ --------eqn 1

The angle through which the first minima is diffracted is given by $tan\Theta =\frac{y_1}{D}$ ---------eqn 2

As $\Theta$ is very small so we can write $sin\Theta =tan\Theta$

So from eqn 1 and eqn 2 we can write

$y_1=\frac{1.22\lambda D}{d}$ --------eqn 3

Here $y_1$ is the position of first maxima D is the distance of screen from the circular aperture d is the diameter of aperture

It is given that diameter of circular aperture is 14.7 cm so $y_1=\frac{14.7}{2}=7.35 \ cm$

Now putting all these value in eqn 3

$d=\frac{1.22\lambda D}{y_1}$

$d=\frac{1.22\times 640\times 10^{-9}\times 21.7}{7.35\times 10^{-2}}=2305.21\times 10^{-7}m$

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2 years ago

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Rus_ich [418]

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3 years ago

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Answer:

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3 years ago

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Romashka-Z-Leto [24]

Explanation:

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