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MA_775_DIABLO [31]
1 year ago
7

A 112. 6 g mass of unknown material is submersed in 102 ml of water to yield a final volume of 126 ml. What is the apparent dens

ity of the unknown material?.
Chemistry
1 answer:
skad [1K]1 year ago
4 0

The density of the unknown material is 0.213 ml/g

<h3>Apparent density of the unknown material</h3>

The apparent density of the unknown material is calculated as follows;

Volume of the unknown substance = 126 ml - 102 ml = 24 ml

Density of the unknown substance = mass/volume

Density of the unknown substance =  24 ml / 112.6 g

Density of the unknown substance = 0.213 ml/g

Thus, the density of the unknown material is 0.213 ml/g

Learn more about density here; brainly.com/question/6838128

#SPJ1                          

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8 0
3 years ago
Calculate the mass of NaCl needed to make 40% solution from 3kg of water ? Could you explain step by step please :-)
earnstyle [38]
Ok so 40 percent of 3000 grams which is 3 kg is 1200 grams 
So you would need 1.2kg or 1200 grams to make a 40% solution
3 0
4 years ago
ObIel WiLll unt COl.. USSMS A certain chemical reaction releases 31.2 kJ/g of heat for each gram of reactant consumed. How can y
aleksandr82 [10.1K]

Answer:

The expression to calculate the mass of the reactant is m = \frac{1.080kJ}{31.2kJ/g}

Explanation:

<em>The amount of heat released is equal to the amount of heat released per gram of reactant times the mass of the reactant.</em> To keep to coherence between units we need to transform 1,080 J to kJ. We do so with proportions:

1,080J.\frac{1kJ}{10^{3}J } =1.080kJ

Then,

1.080kJ=31.2\frac{kJ}{g} .m\\m = \frac{1.080kJ}{31.2kJ/g}

5 0
4 years ago
Read 2 more answers
"A solution with a total volume of 850.0 mL contains 43.5 g Mg(NO3)2. If you remove 25.0 mL of this solution and then dilute thi
ycow [4]

Answer: C = 0.014M

Explanation:

From n= m/M= CV

m =43.5 M= 148, V=850ml

43.5/148= C× 0.85

C= 0.35M

Applying dilution formula

C1V1=C2V2

C1= 0.35, V1= 25ml, C2=?, V2= 600ml

0.35× 25 = C2× 600

C2= 0.014M

7 0
4 years ago
The theoretical yield of 1,2-epoxycyclohexane is _______________ grams, when starting with 3.0 grams of trans-2-bromocyclohexano
Amanda [17]

Answer:

1.64g

Explanation:

The reaction scheme is given as;

2-bromocyclohexanol  --> 1,2-epoxycyclohexane + HBr

From the reaction above,

1 mol of 2-bromocyclohexanol produces 1 mol of 1,2-epoxycyclohexane

3.0 grams of trans-2-bromocyclohexanol.

Molar mass = 179.05 g/mol

Number of moles = mass / molar mass = 3 / 179.05 = 0.016755 mol

This means  0.016755 mol of 1,2-epoxycyclohexane would be produced.

Molar mass =  98.143 g/mol

Theoretical  yield = Number of moles * Molar mass

Theoretical  yield =  0.016755 * 98.143 ≈ 1.64g

7 0
3 years ago
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