<em>M CaCl₂: 40+(35,5×2) = 111 g/mol</em>
6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
X = (75,9×<span>6,02·10²³)/111
X = <u>4,116</u></span><span><u>·10²³</u> molecules of CaCl</span>₂
:)
Answer:
Hope this helps:
Explanation:
I think that it might be C. I'm not an expert so please don't blame me, I'm sorry if i'm wrong!
Answer:
Explanation:
The measurement <em>1246g</em> shows four figures. To show this measurement to <em>three signficant figures</em> you must change the last digit to 0 and round properly.
To report the measurement 1246g to three significant figures you must replace the last digit (the 6) with 0 and round the previous one (the 4) to the closest integer: 1250 is closest to 1246 than 1240, so the correct rounding is 1250.
In an integer number, the zeros after the last none zero digit are not sginificant figures; that is why the zero in 1250 g is not significant and this number has just three significant figures.
