Answer:
805.6 moles
Explanation:
Molarity = 1.52mL
Volume = 530mL
1.52 moles is present in 1mL,
1mL = 0.001L
1.52 moles = 0.001L
X moles = 0.53L
X = (1.52 × 0.53) / 0.001
X = 805.6moles
805.6moles is present in 530mL or 0.52L
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution. (Option a)
<h3>Strength of electrolytes</h3>
- Strong electrolytes: are completely ionized in aqueous solution.
- Weak electrolytes: are partially ionized in aqueous solution.
Let's consider the ionization of ammonium hydroxide, which is a weak base.
NH₄OH ⇄ NH₄⁺ + OH⁻
Why is it considered a weak base?
a. it produces few hydroxide ions in aqueous solution. Yes, since it dissociates partially.
b. it produces few hydrogen ions in aqueous solution. No, since it does not produce hydrogen ions.
c. it does not conduct electricity in aqueous solution. No, since it conducts electricity, although poorly.
d. it will not take part in a neutralization reaction. No, since it will be neutralized by acids.
Ammonium hydroxide is considered a weak base because it produces few hydroxide ions in aqueous solution.
Learn more about weak bases here: brainly.com/question/322250
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They give a double displacement reaction where the ions switch places and give sodium nitrate (NaNO3) and silver chloride (AgCl) as the products. Silver nitrate is also very soluble in water, but silver chloride is highly insoluble in water and will precipitate out of solution as a white solid.
The number of mole of nitrogen gas, N₂, needed to produce 150 g of ammonia, NH₃ is 4.41 moles
<h3>How to determine the mole of NH₃ produced </h3>
- Mass of NH₃ = 150 g
- Molar mass of NH₃ = 14 + (3×1) = 17 g/mol
Mole = mass /molar mass
Mole of NH₃ = 150 / 17
Mole of NH₃ = 8.82 moles
<h3>How to determine the mole of N₂ needed </h3>
Balanced equation
N₂ + 3H₂ —> 2NH₃
From the balanced equation above,
2 moles of NH₃ were produced by 1 mole of N₂.
Therefore,
8.82 moles of NH₃ will be produced by = 8.82 / 2 = 4.41 moles of N₂.
Thus, 4.41 moles of N₂ is needed for the reaction.
Learn more about stoichiometry:
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V2O5 is the formula. Vanadium has a charge of +5 and oxygen is -2, so to make them equal, you need to double the vanadium charge and multiply the oxygen charge by 5
