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1 year ago

Which number line best shows how to solve −8 − (−2)? (5 points)

1 answer:

6 0

A number line from negative 10 to 10 is shown, with numbers labelled at intervals of 2. An arrow is shown from point 0 to negative 8. Another arrow points from negative 8 to negative 6. Therefore, option C is the correct answer.

<h3>What is a number line?</h3>

A number line is a straight line with numbers placed at equal intervals. Positive numbers are placed to the right of 0 and negative numbers are placed to the left of zero.

When a number (x) is added x unit is moved to the right while if a number (x) is subtracted x unit is moved to the left.

Now, solve -8 - (-2)

= -8 + 2=-6

So, a number line from negative 10 to 10 with numbers labelled at intervals of 2. An arrow is shown from point 0 to negative 8 then since 2 is added, we move 2 units right from negative 8 to negative 6.

Therefore, option C is the correct answer.

To learn more about the number line visit:

brainly.com/question/13189025.

#SPJ1

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Answer:

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Step-by-step explanation:

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2 years ago

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2 years ago

Jay and Blair went fishing. Together, they caught 27 fish. Jay caught 2 times as many fish as Blair. How many fish did Jay and B

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3 years ago

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Rom4ik [11]

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2 years ago

Construct a 95% confidence interval for the population mean, mu. Assume the population has a normal distribution. A random sam

aniked [119]

Given Information:

Number of lithium batteries = n = 16

Mean life of lithium batteries = μ = 645 hours

Standard deviation of lithium batteries = σ = 31 hours

Confidence level = 95%

Required Information:

Confidence Interval = ?

Answer:

$CI = 628.5 \: to \: 661.5 \: hours$

Step-by-step explanation:

The confidence interval is given by

$CI = \mu \pm t_{\alpha/2} (\frac{\sigma}{\sqrt{n}})$

Where μ is the mean life of lithium batteries, σ is the standard deviation, n is number of lithium batteries selected, and t is the critical value from the t-table with significance level of

tα/2 = (1 - 0.95) = 0.05/2 = 0.025

and the degree of freedom is

DoF = n - 1 = 16 - 1 = 15

The critical value (tα/2) at 15 DoF is equal to 2.131 (from the t-table)

$CI = 645 \pm 2.131(\frac{31}{\sqrt{16}})$