All categories

3 years ago

What is M=35g, V=17cm³

Physics

1 answer:

cestrela7 [59]3 years ago

6 0

Answer: 25

Explanation:

You might be interested in

What does the ideal gas law allow a scientist to calculate that the other gas laws do not?

Anvisha [2.4K]

The ideal gas law allows a scientist to calculate the number of moles that the other gas laws do not. The ideal gas law is given as

P V = n RT

rearranging the equation by dividing both side by "RT", we get

PV/(RT) = nRT/(RT)

n = PV/(RT)

inserting the values of pressure, volume and temperature, we get number of moles.

7 0

3 years ago

Read 2 more answers

A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc

ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

$T=2\pi \sqrt{\frac{L}{g} }$

Where T is period

L is length of rod

g is acceleration due to gravity = $9.8m/s^{2}$

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this $L_{O}$

$L_{O} = 3/4 * 5.95m$

= 4.4625m

thus $T=2\pi \sqrt{\frac{L_{O} }{g} }$

$T=2\pi \sqrt{\frac{4.4625 }{9.8} }$

T= 4.24sec

8 0

4 years ago

In a double-slit experiment, the third-order maximum for light of wavelength 490 nm is located 15 mm from the central bright spo

jeka94

Answer:

The distance from the central bright spot are $156.8\times10^{-3}\ mm$ and $142.9\times10^{-3}\ mm$ .

Explanation:

Given that,

Wavelength = 490 nm

Distance y= 15 mm

Length L=1.6 m

New wavelength = 670

We need to calculate the distance from the central bright spot

Using formula of distance

$y= \dfrac{m\lambda L}{d}$

$d=\dfrac{m\lambda L}{y}$

Put the value into the formula

$d=\dfrac{3\times490\times10^{-9}\times1.6}{15\times10^{-3}}$

$d=156.8\times10^{-6}\ m$

$d=156.8\times10^{-3}\ mm$

We need to calculate the distance from the central bright spot for new wavelength

Using formula of distance

$d=\dfrac{m\lambda L}{y}$

Put the value into the formula

$d=\dfrac{2\times670\times10^{-9}\times1.6}{15\times10^{-3}}$

$d=142.9\times10^{-6} m$

$d=142.9\times10^{-3}\ mm$

Hence, The distance from the central bright spot are $156.8\times10^{-3}\ mm$ and $142.9\times10^{-3}\ mm$ .

8 0

3 years ago

What is the unit for current? <br> a. a <br> b. c <br> c. i <br> d. t

anzhelika [568]

It is Amperes(A), so the answer is A

7 0

4 years ago

A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done in the process

ivann1987 [24]

Answer: Cannot determine cause we need to know the change of time to calculate the work.

Explanation:

m = 0.5kg

V = 3m/s - 5m/s = -2m/s

P = W/t = Fv

F = ma

W = Fvt

W = (0.5)(9.8)t = 4.9t

4 0

2 years ago

What is M=35g, V=17cm³​

What is M=35g, V=17cm³