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2 years ago

Observe Record the appearance (colors,

Chemistry

2 answers:

qwelly [4]2 years ago

8 0

Answer: Zn is an element and CuSO4 is an ionic compound.

Explanation: Got it right on EDG2020 :)

Naddika [18.5K]2 years ago

3 0

Answer:

1) Zn is a element

2)CuSO4 is an ionic compound

Explanation:

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How would someone describe a passing grade

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A passing grade is a grade that makes a person eligible to go to the next grade.

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2 years ago

The number 875000 written in scientific notation would be

babymother [125]

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8.75 x 10^5

Explanation:

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3 years ago

Convert 682000000000 kmol to Tmol

Elena-2011 [213]

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2 years ago

Read 2 more answers

Consider the following reaction:

Kitty [74]

Answer : The value of equilibrium constant (Kc) is, 0.0154

Explanation :

The given chemical reaction is:

$SO_2Cl_2(g)\rightarrow SO_2(g)+Cl_2(g)$

Initial conc. $2.4\times 10^{-2}$ 0 0

At eqm. $(2.4\times 10^{-2}-x)$ x x

As we are given:

Concentration of $Cl_2$ at equilibrium = $1.3\times 10^{-2}M$

That means,

$x=1.3\times 10^{-2}M$

The expression for equilibrium constant is:

$K_c=\frac{[SO_2][Cl_2]}{[SO_2Cl_2]}$

Now put all the given values in this expression, we get:

$K_c=\frac{(x)\times (x)}{2.4\times 10^{-2}-x}$

$K_c=\frac{(1.3\times 10^{-2})\times (1.3\times 10^{-2})}{2.4\times 10^{-2}-1.3\times 10^{-2}}$

$K_c=0.0154$

Thus, the value of equilibrium constant (Kc) is, 0.0154

4 0

3 years ago

What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid =

laiz [17]

<span>What is the ph of an acetic acid solution if 10 drops are titrated with 70 drops of a 0.65 m koh solution? (ka for acetic acid = 1.8 x 10-5)?

[KOH] = 0.65 M
[OH] = 0.65 M
</span>Dilute your mom
<span>[OH]Dil= 0.65 M * 70/80 = 0.56875 M

pH = 5.4
</span>

7 0

2 years ago