When there are 14c-lable uracil that are added to the growth medium of cells, the macromolecules that will be labled are RNA. Uracil is a nucleobase that make up the DNA or the RNA. In RNA, uracil binds with other nucleobase (adenine) through hydrogen bonds.
Answer:.633
Explanation:
I have know idea but it was right
Esto se queda igual entonces el lo mejor
Answer:
Explanation
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One
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Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + H2O
Focus on the NO3. This is an odd problem and you usually do not focus on the complex ion. But this one works easiest if you do.
The problem now is going to be the oxygens. There are 2 with the Calcium and only 1 free one going to the water. (The NO3 has been taken care of in the last step).
Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O
Count the atoms. I think this equation is balanced.
atom Left Right Result
Ca 1 1 Balanced
O 8 8 Balanced
H 2 + 2 2*2 Balanced
N 2 2 Balanced
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Two
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CH4 + O2====> CO2 + H2O
Start with the hydrogens.
The right side requires a 2
CH4 + O2 ===> CO2 + 2H2O
Now look at the oxygens. There are 4 on the right. and only 2 on the left. You need to multiply O2 by 2
CH4 + 2O2 ===> CO2 + 2H2O
Each side has 1 Carbon 4 hydrogens and 4 oxygens. The equation is balanced.
Answer:
4.3 × 10²¹ atoms
Explanation:
Step 1: Calculate the moles corresponding to 0.24 g of CaCO₃
The molar mass of CaCO₃ is 100.09 g/mol.
0.24 g × (1 mol/100.09 g) = 2.4 × 10⁻³ mol
Step 2: Calculate the moles of oxygen in 2.4 × 10⁻³ moles of CaCO₃
The molar ratio of CaCO₃ to O is 1:3. The moles of O are 3/1 × 2.4 × 10⁻³ mol = 7.2 × 10⁻³ mol
Step 3: Calculate the number of O atoms in 7.2 × 10⁻³ moles of O
We will use Avogadro's number: there are 6.02 × 10²³ atoms of O in 1 mole of atoms of O.
7.2 × 10⁻³ mol × (6.02 × 10²³ atoms/1 mol) = 4.3 × 10²¹ atoms