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disa [49]
1 year ago
8

Suppose you need your silicon circuit element to run continuously for 3 minutes before it shuts off long enough to cool back dow

n to its initial temperature. If the circuit element can withstand a temperature change of 5.1 ∘C without being damaged, what is the maximum rate at which energy can be added to the circuit element?
Physics
1 answer:
Zigmanuir [339]1 year ago
3 0

The maximum rate at which energy can be added to the circuit element mathematically given as

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

<h3>What is the maximum rate at which energy can be added to the circuit element?</h3>

Generally, the equation for P is  mathematically given as

P=\ln s \frac{\Delta T}{\Delta t}

Therefore

Rate\ of\ Change\ of\ Temp =\frac{p}{lnS}

\frac{p}{lnS}=\frac{7.4 \times 10^{-3}}{23 \times 10^{-6} \times 705}

\frac{p}{lnS}=0.456^{\circ \mathrm{c}} / \mathrm{sec}

Max temp Change

MaxT=5.6^{\circ} \mathrm{C}

\text { time }=3 \times 60

t=180s

In conclusion, Max Energy Rate

MER =23 \times 10^{-6} \times \frac{301 \times 5.6}{180}

MER=5.044 \times 10^{-4} \mathrm{~J} / \mathrm{sec}

Read more about  Energy

brainly.com/question/13439286

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Different temperatures

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It which medium would light have the longest wavelength
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on a recent adventure trip, Anita Break went rock climbing. Anita was able to perform 1370 J of work in 100 seconds. Determine A
Zanzabum

        Power = (energy) / (time)

         =    (1370 joules) / (100 seconds)

         =       13.7  joules/second

         =       13.7 watts .

That's not an awful lot of power, especially for a strenuous activity like
rock-climbing.  Shoot !  Even I could probably perform at that level.

Compare 13.7 watts to the light power coming out of a 20-watt night light.

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5 0
3 years ago
lasie4. A 4 kg object is displaced to the right by a distance of 12 m underthe influence of the following forces: a 17 Nforce pu
Oksanka [162]

The work done by a constant force in a rectilinear motion is given by:

W=Fd\cos\theta

where F is the magnitude of the force, d is the distance and θ is the angle between the force and the displacement vector.

In this case we have two forces then we need to add the work done by each of them; for the first force we have a magnitude of 17 N, a displacement of 12 m and and angle of 0° (since both the displacement and the force point right); for the second force we have a magnitude of 36 N, a displacement of 12 m and an angle of 30°. Plugging these values we have that the total work is:

\begin{gathered} W=(17)(12)\cos0+(36)(12)\cos30 \\ W=578.123 \end{gathered}

Therefore, the total work done is 578.123 J and the answer is option E

6 0
11 months ago
A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

7 0
2 years ago
Read 2 more answers
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