The solution would be like
this for this specific problem:
<span>
The force on m is:</span>
<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] ->
1
The force on 2m is:</span>
<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2]
-> 2
From (1), you’ll get M = 2mx^2 / L^2 and from
(2) you get M = m(L - x)^2 / L^2
Since the Ms are the same, then
2mx^2 / L^2 = m(L - x)^2 / L^2
2x^2 = (L - x)^2
xsqrt2 = L - x
x(1 + sqrt2) = L
x = L / (sqrt2 + 1) From here, we rationalize.
x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1)
x = L(sqrt2 - 1) / (2 - 1)
x = L(sqrt2 - 1) </span>
= 0.414L
<span>Therefore, the third particle should be located the 0.414L x
axis so that the magnitude of the gravitational force on both particle 1 and
particle 2 doubles.</span>
Answer:
Friction force on the bullet is 58.7 N opposite to its velocity
Explanation:
As we know that initial speed of the bullet is 55 m/s
after travelling into the sand bag by distance d = 1.34 m it comes to rest
so final speed
now we can use kinematics top find the acceleration of the bullet
so we have
now by Newton's II law we know that
so we have
Answer:
300 miles per hour
Explanation:
Speed is distance per unit time, expressed as s=d/t where t is the time taken, d is distance covered and s is the speed.
Convering s to hrs
To convert seconds to hours, we knkw that 1 hour has 60 minutes and each minute has 60 seconds. Therefore, 1 hour has 60*60=3600 seconds
If 3600s=1 h
60 s=?
By cross multiplication 60s*1 h/3600s=1/60 hours
Given distance as 5 miles and time as 1/60 hours then the speed will be 5 divided by 1/60 hrs which is equivalent to 5*60=300 miles per hour
Answer:
P = 140000 [Pa]
Explanation:
To solve this problem we must remember that pressure is defined as the relationship between Force on the area of a body.
In this particular problem, we are given the force acting on the upper surface of the block, including the force exerted by the atmospheric pressure.
P = F/A
where:
P = pressure [Pa] (units of Pascals)
F = force = 3.5*10⁴ [N]
A = area = 0.25 [m²]
P = 3.5*10⁴/0.25
P = 140000 [Pa]
