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PilotLPTM [1.2K]
2 years ago
10

What is the term for a type of reaction in which an acid and a base react to produce a salt and water?

Chemistry
1 answer:
WINSTONCH [101]2 years ago
5 0
Neutralization 
is the probable answer, which I don't know how to explain, but I know that's the answer because I learned about it a few years ago and I'm pretty smart. =]

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Where is most of the high-level waste from nuclear reactors stored?
Nana76 [90]
It's stored at the reactor site.
7 0
2 years ago
How many liters of CO2 are in 4.76 moles? (at STP)
dem82 [27]

<u>Answer:</u> The volume of carbon dioxide gas at STP for given amount is 106.624 L

<u>Explanation:</u>

We are given:

Moles of carbon dioxide = 4.76 moles

<u>At STP:</u>

1 mole of a gas occupies a volume of 22.4 Liters

So, for 4.76 moles of carbon dioxide gas will occupy a volume of = \frac{22.4L}{1mol\times 4.76mol=106.624L

Hence, the volume of carbon dioxide gas at STP for given amount is 106.624 L

6 0
3 years ago
Concerning Boyle's Law, if you had a gas at a pressure of 101 kPa and decreased the volume of the container holding the gas to o
Viefleur [7K]

Answer:

P_2=404 kPa

Explanation:

Hello,

In this case, the Boyle's is mathematically defined via:

P_1V_1=P_2V_2

Which stands for an inversely proportional relationship between volume and pressure, it means the higher the volume the lower the pressure and vice versa. In such a way, since the volume is decreased to one quarter, we can write:

V_2=\frac{1}{4} V_1

We can compute the new pressure:

P_2=\frac{P_1V_1}{V_2} =\frac{P_1V_1}{\frac{1}{4} V_1} =\frac{101kPa*V_1}{\frac{1}{4} V_1} \\\\P_2=4*101kPa\\\\\\P_2=404 kPa

Which means the pressure is increased by a factor of four.

Regards.

7 0
2 years ago
Which elements usually lose their valence electrons when they bond
masya89 [10]
Metals, for example Cesium and Francium
5 0
3 years ago
Read 2 more answers
What is the vapor pressure of an aqueous solution made up of 60.0g of urea (CH4N2O) in 180g of water? the vapor pressure of wate
djyliett [7]
To get the answer you use the Law of Raoult.


Raoult's law states that the decrease of the vapor pressure of a liquid is proportional to the molar fraction of the solute.


ΔP = Pa * Xa


Here Pa = 0.038 atm


And Xa = N a / (Na + Nb), where Na is number of moles of A and Nb is number of moles of b


Na = mass of urea / molar mass of urea =  60 g / (molar mass of CH4N2O)


molar mass of CH4N2O = 12 g/mol + 4*1g/mol + 2*14 g/mol + 16 g/mol = 60 g/mol


Na = 60 g / 60 g/mol = 1 mol


Nb = mass of water / molar mass of water = 180g / 18g/mol = 10 mol


Xa = 1 mol / (10 mol + 1 mol) = 1/11 =0.09091


ΔP = Pb * Xa = 0.038 atm * 0.09091 =  0.0035 atm


Then, the final vapor pressure of water is Pb - ΔP = 0.038atm - 0.0035atm = 0.035 atm.


 Answer: 0.035 atm
7 0
3 years ago
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