Answer:
12.7g of Cu
Explanation:
First let us generate a balanced equation for the reaction. This is illustrated below:
Zn + CuSO4 —> ZnSO4 + Cu
Molar Mass of Cu = 63.5g/mol
Molar Mass of CuSO4 = 63.5 + 32 + (16x4) = 63.5 + 32 + 64 = 159.5g/mol
From the equation,
159.5g of CuSO4 produced 63.5g of Cu.
Therefore, 31.9g of CuSO4 will produce = (31.9 x 63.5) / 159.5 = 12.7g of Cu
Answer:
Explanation:
Hello!
In this case, since the molecular formula of glycine is C₂H₅NO₂, we realize that the molar mass is 75.07 g/mol; thus, the moles in 130.0 g of glycine are:
Furthermore, we can notice 75.07 grams of glycine contains 14.01 grams of nitrogen; thus, the percent nitrogen turns out:
Best regards!
You always adjust numbers and it will be before the element
so you Neva add or change a subscript
Answer:
kilopascal, torr, and atmosphere
Explanation:
84.24 g of water (H₂O)
Explanation:
We have the following chemical reaction:
2 H₂O → 2 H₂ + O₂
Now we calculate the number of moles of products.
number of moles = mass / molar weight
number of moles of H₂ = 50 / 2 = 25 moles
number of moles of O₂ = 75 / 32 = 2.34 moles
We see from the chemical reaction that for every 2 moles of H₂ produced there are 1 mole of O₂ produces for every 25 moles of H₂ produced there are 12.5 moles of O₂ but we only have 2.35 moles of O₂ available. The O₂ will be the limiting quantity from which we devise the following reasoning:
if 2 moles of H₂O produces 1 mole of O₂
then X moles of H₂O produces 2.34 mole of O₂
X = (2 × 2.34) / 1 = 4.68 moles of H₂O
mass = number of moles × molar weight
mass of H₂O = 4.68 × 18 = 84.24 g
Learn more about:
limiting reactant
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