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xenn [34]
3 years ago
15

Is 0.0 m/s squared increasing or decreasing

Physics
1 answer:
Agata [3.3K]3 years ago
4 0
Decrease because its 0.0 m/s
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The r force is the overall force. If two forces are acting in the same direction, the resultant force is the s of all the forces
notka56 [123]

The resultant force is the overall force. If two forces are acting in the same direction, the resultant force is the sum of all the forces.

Happy to help!

5 0
3 years ago
An electron that has a velocity with x component 2.6 × 106 m/s and y component 4.0 × 106 m/s moves through a uniform magnetic fi
Natasha2012 [34]

Explanation:

It is given that,

The horizontal and vertical component of velocity of an electron is:

v=(2.6i+4j)\times 10^6\ m/s

The magnetic field acting there is given by :

B=(0.037i-0.17j)\ T

(a) The magnitude of the magnetic force on the electron is given by :

F=q(v\times B)

q = e

F=e(v\times B)

F=1.6\times 10^{-19}\times ((2.6i+4j)\times 10^6\times (0.037i-0.17j))

F=-1.6\times 10^{-19}\times (-0.442\cdot10^{6}-0.1702\cdot10^{6})\ kN

F=9.79\times 10^{-14}\ kN

(b) We know that the charge on proton is :

q=+1.6\times 10^{-19}\ C

The magnetic force as same as for electron but the direction is opposite i.e.

F=-9.79\times 10^{-14}\ kN

Hence, this is the required solution.

4 0
3 years ago
A sprinter explodes out of the starting block with an acceleration of +4.2 m/s2, which she sustains for 0.9 s. Then, her acceler
ad-work [718]

Answer:

a) 3.78 m/s

b) 3.78 m/s

Explanation:

a )From the equations of kinematics   we know that

     Vf - Vi = at

since Initial speed Vi = 0

acceleration = 4.2 m/s2

so we have

     Vf = a t

           = (4.2) (0.9)

         = 3.78 m/s

velocity at t = 0.9 s. m/s is 3.78 m/s

b) If the sprinter maintains constant velocity then acceleration becomes zero.

   So velocity is 3.78 m/s

6 0
3 years ago
Pls help. Ill give 10 pts each for the other 3 questions i asked. look at my account and the other three questions will increase
jasenka [17]

Answer:

a = 0.273 m/s²

Explanation:

I would assume that the rider starts at 0m/s.

a = average acceleration

v = final velocity = 3 m/s

v0 = initial velocity = 0 m/s

t = time = 11 s

a = (v-v0)/t

a = (3m/s - 0m/s) / 11s

a = 0.273 m/s²

I am not sure how many decimals I should round it to, so I just gave three. If your teacher has instructions on that, do so accordingly.

5 0
3 years ago
If two alpha particles (each with two protons and two neutrons) are 0.500 m apart, what is the electric potential energy of the
elena-14-01-66 [18.8K]

Answer:

U = 1.84 10⁻²⁷ J

Explanation:

Electric potential energy is

        U = k q₁q₂/ r

in this case the electric charge is

         q = 2 p

         q = 2 1.6 10⁻¹⁹

         q = 3.2 10⁻¹⁹ C

indicate the distance between the charges is 0.500 m

we calculate

         U = 9 10⁹  3.2 10⁻¹⁹  3.2 10⁻¹⁹ /0.500

         U = 1.84 10⁻²⁷ J

8 0
3 years ago
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