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xenn [34]
3 years ago
15

Is 0.0 m/s squared increasing or decreasing

Physics
1 answer:
Agata [3.3K]3 years ago
4 0
Decrease because its 0.0 m/s
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3 years ago
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Calculate A, E, μ, cv and S for 1 mole of Kr at 298 K and 1 atm (assuming ideal behavior)
vaieri [72.5K]

Answer:

internal energy E 3716.35 j

cv = 12.47 J/K

S = 12.47 J/K

A =  0.29 J

\mu =3716.35 J/mole

Explanation:

given data:

Kr  atomic number = 36

degree of freedom = 3

1) internal energy E = \frac{f}{2} n R T

                                = \frac{3}{2} *1*8.314*298 = 3716.35 j

2) cv = \frac{E}{T}

         = \frac{3716.35}{298} = 12.47 J/K

3) S = cv =\frac{E}{T} = 12.47 J/K

4) A, Halmholtz free energy = E -TS = 37146.35 - 12.47*298 = 0.29 J

5)chemcial potential \mu = \frac{energy}{mole} = 3716.35 J/mole

6 0
3 years ago
Why are not all microorganism harmful?
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 There are some microorganisms which are helpful to man and they live mostly on the skin of man or in his gut and are mostly bacteria. They are collectively called bacterial normal flora.

In man the normal bacterial flora of the skin include staphylococcus found on dry skin, cornybacteria found in moist skin sites and propionibacteria in the sebaceous sites (head, neck, trunk) of the body. Normal bacterial flora of the gut include Escherichia coli.

One of the major function of bacterial flora is actually to protect our bodies  by competing for space with pathogens preventing them from gaining a foothold in our bodies.



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Dynamo converts the
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Answer:

\gamma  \: dynamo \: converts \: the \: mechanical \: energy \: into \: electrical \: energy \: .

Explanation:

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Car A is traveling west at 40 mi/h and car B is traveling north at 40 mi/h. Both are headed for the intersection of the two road
Gwar [14]

Explanation:

It is given that,

    \frac{dx}{dt} = -40 mi/h,     \frac{dx}{dt} = -40 mi/h

The negative sign indicates that x and y are decreasing.

We have to find \frac{dz}{dt}. Equation for the given variables according to the Pythagoras theorem is as follows.

              z^{2} = x^{2} + y^{2}

Now, we will differentiate each side w.r.t 't' as follows.

        2z\frac{dz}{dt} = 2x\frac{dx}{dt} + 2y\frac{dy}{dt}

or,          \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

So, when x = 4 mi, and y = 3 mi then z = 5 mi.

As,       \frac{dz}{dt} = \frac{1}{z}(x\frac{dx}{dt} + y\frac{dy}{dt})

                       = \frac{1}{5}(4 \times (-40) + 3 \times (-40))

                       = \frac{-140 - 120}{5}

                       = 52

Thus, we can conclude that the cars are approaching at a rate of 52 mi/h.

7 0
3 years ago
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