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2 years ago

Find the acceleration of a hamster when it increases its velocity from rest to 8.0 m/s in 3.0 s .

1 answer:

6 0

Acceleration is the change in velocity divided by time.
We can find acceleration a, by the following formula

a=v-u/t

where,
v is the final velocity (in this question v=8.0 m/s)
u is the initial velocity (since the hamster starts from rest, u=0)
t is the time taken (i,e 3.0 second)
now by applying the formula we have,

a = 8.0 - 0 / 3
= 8 / 3
= 2.65 m/s²

The acceleration is 2.65 meters per second squared

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Do you think distance and time are relevant terms in describing motion?

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Answer:

yes

Explanation:

because motion is relevant

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2 years ago

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A transformer supplies 60 watts of power to a device that is rated at 20 volts. The primary coil is connected to a 120-volt ac s

Alex777 [14]

Answer:

The current in the primary coil would be $0.5\ A$ .

Explanation:

Given the power supplied by a transformer is 60 watts.

And the voltage in the primary coil is 120 Volts.

We need to find the current supply in the primary coil.

We will use the formula

$P=V\times I$

Where,

$P$ is the power in Watts.

$V$ is the voltage in Volts.

$I$ is the current supply in Ampere.

$I=\frac{P}{V}\\\\I=\frac{60}{120}\\ \\I=0.5\ A$

So, the current in the primary coil would be $0.5\ A$ .

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2 years ago

The mass of the sun is 1.99x10^30 kg . Jupiter is 7.79x10^8 km away from the sun and the mass of 1.90x10^27 kg

maks197457 [2]

Question is missing:

"What is the gravitational force between the Sun and Jupiter?"

Answer:

$4.16\cdot 10^{23} N$

Explanation:

The gravitational force between two objects is given by

$F=G\frac{m_1m_2}{r^2}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the objects

In this problem, we have

$m_1 = 1.99\cdot 10^{30} kg$ is the mass of the sun

$m_2 = 1.90\cdot 10^{27} kg$ is the mass of Jupiter

$r=7.79\cdot 10^8 km = 7.79\cdot 10^{11} m$ is their separation

Solving the equation, we find

$F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(1.90\cdot 10^{27})}{(7.79\cdot 10^{11})^2}=4.16\cdot 10^{23} N$

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2 years ago

How long (in seconds) does it take a car accelerating at 3.1 m/s2 to go from rest to 51 m/s?

Nesterboy [21]

Answer:

t = 16.5s

Explanation:

Given parameters:

Acceleration = 3.1m/s²

Initial velocity = 0m/s

Final velocity = 51m/s

Unknown:

Time taken = ?

Solution:

To solve this problem we need to reiterate that acceleration is the rate of change of velocity with time.

So;

Acceleration = $\frac{v - u }{t}$

v is the final velocity

u is the initial velocity

t is the time taken

So;

3.1 = $\frac{51 - 0}{t}$

3.1t = 51

t = 16.5s

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2 years ago

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Naddik [55]

Hey there!

Your answer: Spilling breaker

Spilling breaker usually occurs when a beach or ocean is flat, and as the waves of the wind continues to happen, slowly the region would eventually become a slope.

It's almost like play-dough. Let's say that we set a perfect flat surface of play-dough on the table. As we continue slide our hands one direction, doesn't the play dough have more on one side than the other? It eventually contains a slope if you add enough from the first place.

Your answer: Spilling breaker

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