Question

Table B: Enthalpy of Formation of Reactants and Products

Answer 1

The calculated enthalpy values are as follows:

• Total enthalpy of reactants = -103.85 KJ/mol
• Total enthalpy of products = -2057.68 KJ/mol
• Enthalpy of reaction = -1953.83 kJ/mol

What is the enthalpy of the reaction?

The enthalpy of the reaction is determined as follows:

• Enthalpy of reaction = Total enthalpy of products -Total enthalpy of reactants

• Total enthalpy of reactants = (ΔHf of Reactant 1 x Coefficient) + (ΔHf of Reactant 2 x Coefficient)
• Total enthalpy of products= (ΔHf of Product 1 x Coefficient) + (ΔHf of Product 2 x Coefficient)

Equation of reaction equation: C₃H₈ (g) + 5 O(g) → 4 H₂O(g) + 3CO₂(g)

Total enthalpy of reactants = (-103.85 * 1) + (0 * 5)

Total enthalpy of reactants = -103.85 + 0

Total enthalpy of reactants = -103.85 KJ/mol

Total enthalpy of products = (-393.51 * 4) +(-241.82 * 3)

Total enthalpy of products = (-1574.04) + (-483.64)

Total enthalpy of products = -2057.68 KJ/mol

Enthalpy of reaction =  -2057.68 KJ/mol -(-103.85 KJ/mol)

Enthalpy of reaction = -1953.83 kJ/mol

In conclusion, the enthalpy of the reaction is determined from the difference between the total enthalpy of products and reactants.

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