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jek_recluse [69]
3 years ago
11

Eddie tosses his phone up to his friends window, which is 4 m above the ground. what energy conversion takes place with respect

to the phone?
A kinetic energy to elastic potential energy
B elastic potential energy to kinetic energy
C gravitational potential energy to kinetic energy
D kinetic energy to gravitational potential energy
Physics
2 answers:
lora16 [44]3 years ago
7 0

Answer:right answer is D apex

Explanation:

yan [13]3 years ago
3 0
C the anwer is c hope i help
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PLEASE HELP QUICKLY!!!!!
Grace [21]

Answer:

D air

Explanation:

it is not found on the periodic table

brainliest plsssssssssssssssss

3 0
3 years ago
An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.275 T. If the kinetic energy of the electr
xxMikexx [17]

Answer:

Radius, r=2.14\times 10^{-5}\ m

Explanation:

It is given that,

Magnetic field, B = 0.275 T

Kinetic energy of the electron, E=4.9\times 10^{-19}\ J

Kinetic energy is given by :

E=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2E}{m}}

v=\sqrt{\dfrac{2\times 4.9\times 10^{-19}}{9.1\times 10^{-31}}}            

v = 1037749.04 m/s

The centripetal force is balanced by the magnetic force as :

qvB\ sin90=\dfrac{mv^2}{r}

r=\dfrac{mv}{qB}

r=\dfrac{9.1\times 10^{-31}\times 1037749.04}{1.6\times 10^{-19}\times 0.275 }

r=2.14\times 10^{-5}\ m

So, the radius of the circular path is 2.14\times 10^{-5}\ m. Hence, this is the required solution.

3 0
3 years ago
Read 2 more answers
When is the universal theme of a story often revealed?
elena-14-01-66 [18.8K]
It is often revealed <span>at the resolution of the story, when the reader can see how the story ends.</span>
7 0
3 years ago
Read 2 more answers
A 58 g firecracker is at rest at the origin when it explodes into three pieces. The first, with mass 12 g , moves along the x ax
alexdok [17]

Answer:

Explanation:

We shall apply conservation of momentum law in vector form to solve the problem .

Initial momentum = 0

momentum of 12 g piece

= .012 x 37 i since it moves along x axis .

= .444 i

momentum of 22 g

= .022 x 34 j

= .748 j

Let momentum of third piece = p

total momentum

= p + .444 i + .748 j

so

applying conservation law of momentum

p + .444 i + .748 j  = 0

p = - .444 i -  .748 j  

magnitude of p

= √ ( .444² + .748² )

= .87 kg m /s

mass of third piece = 58 - ( 12 + 22 )

= 24 g = .024 kg

if v be its velocity

.024 v = .87

v = 36.25 m / s .

6 0
3 years ago
Accurate forecasts require careful study of the location, size, movement, and characteristics of large _____.
tankabanditka [31]

Answer: B air masses

3 0
3 years ago
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