Answer:
<em>The final temperature is 61.65 °C</em>
Explanation:
mass of copper pot = 2 kg
temperature of copper pot = 20 °C (the pot will be in thermal equilibrium with the room)
specific heat capacity of copper = 385 J/kg-°C
The heat content of the copper pot = = 2 x 385 x 20 = 15400 J
mass of boiling water = 200 g = 0.2 kg
temperature of boiling water = 100 °C
specific heat capacity of water = 4182 J/kg-°C
The heat content of the water = = 0.2 x 4182 x 100 = 83640 J
The total heat content of the water and copper mix = 15400 + 83640 = 99040 J
This same heat is evenly distributed between the water and copper mass to achieve thermal equilibrium, therefore we use the equation
=
+
where is the final temperature of the water and the copper
substituting values, we have
99040 = (2 x 385 x ) + (0.2 x 4182 x
99040 = 770 + 836.4
99040 = 1606.4
= 99040/1606.4 = <em>61.65 °C</em>