Question

The concentration of carbon monoxide (CO), a common air pollutant, is found in a room to be 5.7 x 10^-3 mg/cm^3. How many grams of CO are present in the room if the room’s dimensions measure 3.5m x 3.0m x 3.2m?

Answer 1

The amount, in mg, of CO present in the room will be 191,520 mg.

Stoichiometric problem

The concentration of the gas in the room is 5.7 x $10^{-3}$ mg/cm3.

The dimension of the room is 3.5 m x 3.0 m x 3.2 m. This is equivalent to 350 cm x 300 cm x 320 cm.

We can obtain the volume of the room as:

                  350 x 300 x 320 = 33,600,000 cm3

The concentration is in mg/cm3, meaning that it is mass/volume.

Thus:

 mass = concentration x volume = 5.7 x $10^{-3}$ mg/cm3 x 33,600,000 cm3

                         = 191,520 mg

The mass of CO in the room is 191,520 mg

More on stoichiometric problems can be found here: brainly.com/question/14465605

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