Answer:
Explanation:
Given parameters:
Number of breathe per minute = 15times
Volume of air per breath = 0.5L
Percentage of oxygen in air = 21%
Solution
There are 24 hours in a day.
60minutes makes a hour in a day,
I will breathe:
15 times x 60 x 24 = 21600 times in a day
The volume of air I will take in per day:
A breathe = 0.5L of air
21600breathe = 0.5 x 21600 = 10800L of air
Volume of oxygen I will breathe per day:
x 10800 = 2268L of oxygen
Mixture is obtained when several different substances are mixed together. The mixture can be separated back into its original substances and this is what differs them from compounds. From the given option, the following defines the mixtures:
<span>C. Substances that are combined but do not chemically react. </span>
<h3>Answer:</h3>
The starting material involved in the formation of 5-Oxoheptanal is 1-ethylcyclopent-1-ene as shown in reaction below.
<h3>Explanation:</h3>
Ozone is one of the reactive allotrope of oxygen. It reacts vigorously with unsaturated compounds like alkenes and alkynes. In this reaction alkene and O₃ first react to produce Molozonide which is highly unstable and rearranges to form a stable ozonide as shown in scheme attached below.
Furthermore, the ozonide on reduction is convertwed into ketones and aldehydes respectively.
Answer:
E) 0.0207
Explanation:
The molal concentration, m, is defined as the ratio between moles of solute (In this case, KBr) per kg of solvent (water):
<em>Moles KBr -Molar mass: 119g/mol-</em>
2.21g KBr * (1mol / 119g) = 0.01857moles
<em>Mass solvent:</em>
897g * (1kg / 1000g) = 0.897kg
Molal concentration:
0.01857 moles / 0.897kg =
0.0207m
Right solution is:
<h3>E) 0.0207.
</h3>