Who has the authority to declare a "global emergency"?

Engineering

2 answers:

lyudmila [28]1 year ago

7 0

Answer:

Explanation:

The World Health Organization declared a global health emergency on Thursday as the coronavirus outbreak spread well beyond China, where it emerged last month.

The move reversed the organization’s decision just a week ago to hold off such a declaration. Since then, there have been thousands of new cases in China and clear evidence of human-to-human transmission in several other countries, including the United States.

All of which warranted a reconsideration by the W.H.O.’s emergency committee, officials said.

The declaration “is not a vote of no confidence in China,” said Tedros Adhanom Ghebreyesus, the W.H.O.’s director-general. “On the contrary, the W.H.O. continues to have confidence in China’s capacity to control the outbreak.”

son4ous [18]1 year ago

6 0

Answer:

United nations union Manager

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A new 1.2-ha suburban residential development is to be drained by a storm sewer that connects to the municipal drainage system.

valentinak56 [21]

Answer:

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Explanation:

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6 0

3 years ago

Calculate the viscosity(dynamic) and kinematic viscosity of airwhen

nikitadnepr [17]

Answer:

(a) dynamic viscosity = $1.812\times 10^{-5}Pa-sec$

(b) kinematic viscosity = $1.4732\times 10^{-5}m^2/sec$

Explanation:

We have given temperature T = 288.15 K

Density $d=1.23kg/m^3$

According to Sutherland's Formula dynamic viscosity is given by

${\mu} = {\mu}_0 \frac {T_0+C} {T + C} \left (\frac {T} {T_0} \right )^{3/2}$ , here

μ = dynamic viscosity in (Pa·s) at input temperature T,

$\mu _0$ = reference viscosity in(Pa·s) at reference temperature T0,

T = input temperature in kelvin,

$T_0$ = reference temperature in kelvin,

C = Sutherland's constant for the gaseous material in question here C =120

$\mu _0=4\pi \times 10^{-7}$

$T_0$ = 291.15

$\mu =4\pi \times 10^{-7}\times \frac{291.15+120}{285.15+120}\times \left ( \frac{288.15}{291.15} \right )^{\frac{3}{2}}=1.812\times 10^{-5}Pa-s$ when T = 288.15 K