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ZanzabumX [31]
2 years ago
10

Who has the authority to declare a "global emergency"?​

Engineering
2 answers:
lyudmila [28]2 years ago
7 0

Answer:

Explanation:

The World Health Organization declared a global health emergency on Thursday as the coronavirus outbreak spread well beyond China, where it emerged last month.

The move reversed the organization’s decision just a week ago to hold off such a declaration. Since then, there have been thousands of new cases in China and clear evidence of human-to-human transmission in several other countries, including the United States.

All of which warranted a reconsideration by the W.H.O.’s emergency committee, officials said.

The declaration “is not a vote of no confidence in China,” said Tedros Adhanom Ghebreyesus, the W.H.O.’s director-general. “On the contrary, the W.H.O. continues to have confidence in China’s capacity to control the outbreak.”

son4ous [18]2 years ago
6 0

Answer:

United nations union Manager

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I need ideas for what to build because I have some spare wood.
Misha Larkins [42]

Answer:

small guitar with no strings?

Explanation:

it would be fun to make i think

6 0
3 years ago
What type of engineer makes sure equipment is safe and operational
zvonat [6]

Answer:

mechanical engineer is the best answer

8 0
3 years ago
Two resistors, A and B, individually connect to a 9V battery. A student notices that resistor A is warmer than resistor B. Which
dybincka [34]

Answer:

Resistor B

Explanation:

Since resistance is the opposition to the flow of current in a circuit,

first let assume the two resistors are connected in parallel to the voltage, recall that when connection is in parallel, the different amount of current pass through the resistors depending on the value with the small resistor having  a lower resistance effect hence higher current will pass through

The energy dissipated in each resistor can be calculated as

E=\frac{1}{2}IR^{2}t.

from the formula we can conclude that the energy value will be higher for the resistor with small resistance value. hence more heating effect which will cause it to be warm.

Also when connected individually the current flow from the voltage source will pass through the resistor which when we calculate the energy dissipated, the resistor with smaller value will be higher because it will draw more current which will in turn lead to a heating effect and cause the resistor to be warm. Hence we can conclude that the resistance B has greatest resistance value.

4 0
3 years ago
A structural component in the form of a wide plate is to be fabricated from a steel alloy that has a plane strain fracture tough
sp2606 [1]

Answer:

Not subject to detection

Explanation:

Assuming the value of strain fracture toughness is 77 Mpa \sqrt m

The design stress is half hence \sigma=0.5\times 1400=700 Mpa

Critical flaw size, a_c=\frac {1}{\pi}(\frac {K_{1c}}{Y/sigma})^{2}

Where Y is dimensionless parameter, \sigma is applied stress, K_{1c} is plane strain fracture toughness, a_c is critical length of surface crack

a_c=\frac {1}{\pi}(\frac {77}{1*700})^{2}= 0.0038515496\approx 0.00385m

The critical length of surface crack is therefore 3.85 mm, which is less than detection apparatus size given as 4 mm

Since the critical flaw size is less than the resolution limit of flaw detection apparatus, the critical flaw for this plate is not subjected to detection.

5 0
3 years ago
Bananas are to be cooled from 28°C to 12°C at a rate of 1140 kg/h by a refrigerator that operates on a vapor-compression refrige
Lera25 [3.4K]

Answer:

A) COP = \frac{16.97}{9.8} = 1.731

B) P_{IN} = 0.4763

C) Second law efficiency 4.85%

exergy destruction for the cycle = 9.3237 kW

Explanation:

Given data:

T_1 = 28 degree celcius

T_2 = 12 degree celcius

\dot m = 1140 kg/h

Power to refrigerator = 9.8 kW

Cp = 3.35 kJ/kg degree C

A) Q = \dot m Cp \Delta T

        = 1140 \times 3.35\times (28-12) = 61,104 kJ/h

Q_{abs} = 61,104 kJ/h = 16.97 kJ/sec

COP = \frac{16.97}{9.8} = 1.731

b)

COP ∝ \frac{1}{P_{in}}

P_{in} wil be max when COP maximum

taking surrounding temperature T_H = 20 degree celcius

COP_{max} = \frac{T_L}{T_H- T_L} = \frac{285}{293 - 285} = 35.625

we know that

COP = \frac{heat\ obsorbed}{P_{in}}

P_{IN} = \frac{16.97}{35.62} = 0.4763

c) second law efficiency

\eta_{11} = \frac{COP_R}{(COP)_max} = \frac{1.731}{35.625} = 4.85\%

exergy destruction os given as X = W_{IN} - X_{Q2}

                                                         = 9.8 - 0.473 = 9.3237 kW

8 0
3 years ago
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