Answer:
The water of the saturated clayed soil is 66.67 %.
Explanation:
Given;
mass of saturated clayed soil,
= 600 g
mass of dry soil sample,
= 200 g
mass of water content,
=
-
= 600 g - 200 g = 400 g
The water content is determined as;
![M_w(\%) = \frac{M_s - M_d}{M_s} *100\%\\\\M_w(\%) = \frac{600-200}{600} *100 \% \\\\M_w(\%) = 66.67 \%](https://tex.z-dn.net/?f=M_w%28%5C%25%29%20%20%3D%20%5Cfrac%7BM_s%20-%20M_d%7D%7BM_s%7D%20%2A100%5C%25%5C%5C%5C%5CM_w%28%5C%25%29%20%20%3D%20%5Cfrac%7B600-200%7D%7B600%7D%20%2A100%20%5C%25%20%5C%5C%5C%5CM_w%28%5C%25%29%20%20%3D%2066.67%20%5C%25)
Therefore, the water of the saturated clayed soil is 66.67 %.
Answer:
Mass flow rate= 7.53 kg/sec
Exit Area= 0.108m^2
Explanation:
The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.
I think D. By pressing gradually
That means “ if possible then link”
Answer:
I think it is process or technology