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3 years ago

Which is a pure substance? soda gasoline salt water carbon dioxide

Chemistry

2 answers:

hram777 [196]3 years ago

8 0

Answer: Carbon dioxide is a pure substance.

Explanation: A pure substance is defined when a substance has a single type of molecule. If more than 1 type of molecule is present in a substance, then it is considered as a mixture.

Soda is basically a mixture of water and carbon dioxide. More than 1 type of molecule is present.

Gasoline is a mixture of may gases. More than 1 type of molecule is present.

Salt water contains salt and water molecules, hence it is considered as a mixture.

Carbon dioxide has only 1 type of molecule which is $CO_2$ molecules. Hence, it is a pure substance.

-BARSIC- [3]3 years ago

6 0

Answer:

Carbon dioxide

Explanation:

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Suppose a substance has a heat of fusion equal to 45 calg and a specific heat of 0.75

Varvara68 [4.7K]

Answer:

The substance will be in liquid state at a temperature of 97.3 °C

Note: The question is incomplete. The complete question is given below :

Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0.75 cal/g°C in the liquid state. If 5.0 kcal of heat are applied to a 50 g sample of the substance at a temperature of 24°C, what will its new temperate be? What state will the sample be in? (melting point of the substance = 27°C; specific heat of the solid =0.48 cal/g°C; boiling point of the substance = 700°C)

Explanation:

1.a) Heat energy required to raise the temperature of the substance to its melting point, H = mcΔT

Mass of solid sample = 50 g; specific heat of solid = 0.75 cal/g; ΔT = 27 - 24 = 3 °C

H = 50 × 0.75 × 3 = 112.5 calories

b) Heat energy required to convert the solid to liquid at its melting point at 27°C, H = m×l, where l = 45 cal/g

H = 50 × 45 = 2250 cal

c) Total energy used so far = 112.5 cal + 2250 cal = 2362.5 calories.

Amount of energy left = 5000 - 2362.5 = 2637.5 cal

The remaining energy is used to heat the liquid

H = mcΔT

Where specific heat of the liquid, c = 0.75 cal/g/°C, H = 2637.5 cal, ΔT = temperature change

2637.5 = 50 × 0.75 x ΔT

ΔT = 2637.5 / ( 50*0.75)

ΔT = 70.3 °C

Final temperature of sample = (70.3 + 27) °C = 97.3 °C

The substance will be in liquid state at a temperature of 97.3 °C

5 0

3 years ago

A basic substance consisting of only one kind of atom is called a(n) _____.

juin [17]

Answer is D) Element

6 0

3 years ago

4.2g of cerium reacted with oxygen to form 5.16g of an oxide of cerium. Find

olganol [36]

Answer:

CeO₂

Explanation:

Hello!

In this case, since we are given the mass of both cerium and the cerium oxide, we can first compute the moles of cerium and the moles of oxygen as shown below:

$n_{Ce}=4.2gCe*\frac{1molCe}{140.12gCe}=0.03molCe\\$