Question

A spring with k = 136 N/m is compressed by 12.5 cm. How much elastic potential energy does the

Answer 1

As we know,

• $\boxed{ \boxed{potential \: \: energy = \dfrac{1}{2} k {x}^{2} }}$

where,

• k = 136 N/m

• x = 12.5 cm = 0.125 m

now, let's solve to find potential energy :

• $p = \dfrac{1}{2} \times 136 \times 0.125 \times 0.125$

• $p = \dfrac{68 \times 125 \times 125} {1000 \times 1000}$

• $1.0625 \: \: \: joules$