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Slav-nsk [51]
2 years ago
14

A spring with k = 136 N/m is compressed by 12.5 cm. How much elastic potential energy does the

Physics
1 answer:
Lorico [155]2 years ago
6 0

As we know,

  • \boxed{ \boxed{potential \:  \: energy =  \dfrac{1}{2} k {x}^{2} }}

where,

  • k = 136 N/m

  • x = 12.5 cm = 0.125 m

now, let's solve to find potential energy :

  • p =  \dfrac{1}{2}  \times 136 \times 0.125 \times 0.125

  • p =    \dfrac{68 \times 125 \times 125} {1000 \times 1000}

  • 1.0625 \:  \:  \: joules
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A solid cylinder has a diameter of 17.4 mm and a length of 50.3mm. It's mass is 49g . What is its density of the cylinder in met
Tamiku [17]

Answer:

4 tonne/m³

Explanation:

ρ = m / V

ρ = 49 g / (π (17.4 mm / 2)² (50.3 mm))

ρ = 0.0041 g/mm³

Converting to tonnes/m³:

ρ = 0.0041 g/mm³ (1 kg / 1000 g) (1 tonne / 1000 kg) (1000 mm / m)³

ρ = 4.1 tonne/m³

Rounding to one significant figure, the density is 4 tonne/m³.

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3 years ago
Candice is examining a cell under a microscope. She has identified a cell wall, a nucleus, and a chloroplast. What type of organ
RoseWind [281]

Answer:

A plant

Explanation:

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3 years ago
If you want to play a tune on wine glasses, you’ll need to adjust the oscillation frequencies by adding water to the glasses. Th
jonny [76]

Answer:Reducing mass i.e. water

Explanation:

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f=\frac{1}{2\pi }\sqrt{\frac{k}{m}}

where k =stiffness of the glass

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from the above expression we can see that if mass is inversely Proportional to frequency

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3 years ago
An artificial satellite is in a circular orbit around a planet of radius r= 2.05 x103 km at a distance d 310.0 km from the plane
lubasha [3.4K]

Answer:

\rho = 12580.7 kg/m^3

Explanation:

As we know that the satellite revolves around the planet then the centripetal force for the satellite is due to gravitational attraction force of the planet

So here we will have

F = \frac{GMm}{(r + h)^2}

here we have

F =\frac {mv^2}{(r+ h)}

\frac{mv^2}{r + h} = \frac{GMm}{(r + h)^2}

here we have

v = \sqrt{\frac{GM}{(r + h)}}

now we can find time period as

T = \frac{2\pi (r + h)}{v}

T = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{GM}{(r + h)}}}

1.15 \times 3600 = \frac{2\pi (2.05 \times 10^6 + 310 \times 10^3)}{\sqrt{\frac{(6.67 \times 10^{-11})(M)}{(2.05 \times 10^6 + 310 \times 10^3)}}}

M = 4.54 \times 10^{23} kg

Now the density is given as

\rho = \frac{M}{\frac{4}{3}\pi r^3}

\rho = \frac{4.54 \times 10^{23}}{\frac{4}[3}\pi(2.05 \times 10^6)^3}

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The letter D represents the wavelength
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