Answer:
Explanation:
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In this case, according to the given chemical reaction, it is possible to evidence the 4:3 mole ratio between oxygen and iron (II) chloride; thus, we can compute the moles of the latter that are consumed by the given molecules of the former:
Now, since we have a 0.945-M solution of this iron (II) chloride, the corresponding volume turns out to be:
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In the space of 1 liter, methane gas (ch4) is reacted with 6 moles of water vapor according to the reaction: if at equilibrium state is obtained 4 moles of hydrogen gas, how many moles of methane gas is needed for the equilibrium reaction?
the reaction is
CH4(g) + 2H2O(g) ----> CO2(g) + 4H2 (g)
Kc = 16 / 3
Kc = [CO2] [H2]^4 / [CH4] [H2O]^2
given :
equilibrium concentration
[H2] = 4 moles
so equilibrium concentration of CO2 must be 1 mole
equilibrium concentration of H2O = 6 - 2 = 4
putting values
16 /3 = [1] [4]^4 / [CH4] [4]^2
[CH4] = 0.333 moles
so moles of CH4 required = 1.33 moles
There are
A. 6 significant figures
B.5 sig figs
C.2 sig figs
D.5 sig figs
<span>Dmitri Mendeleev's Periodic Law states that chemical and physical properties repeat themselves in groups of 8.</span>
