The compound that has higher mass percent is Mg3N2 which is 72%
explanation
calculate the % mass of Mg in each compound
% composition of mg= molar mass of Mg/ total molar mass of the compound x100
in MgO = 24 /40 x100 = 60%
in Mg3N2 =72/100 x100 = 72 %
therefore the % composition in Mg3N2 is higher
Answer:
Explanation:
Hello,
In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:
Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:
Best regards.
Answer:
0.4 M
Explanation:
M=moles/Liters
Convert grams to moles (446/223.37=1.99668711)
Convert 5000 mL to liters (5000/1000)
Plug in the values and solve
M=2/5
M=0.4
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➷ The correct answer would be A. Agitation (i.e. stirring)
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