Answer:
Explanation:
Hydrosulfuric acid (H_2S) is considered a 'weak acid." It dissociates in water according to this reaction: H_2 S(aq) + H_2O(t) HS^-(aq) + H_3O^+(aq) k_a = 9 times 10^-8 Hydroiodic acid (HI) is considered a "strong acid".
A solution (in this experiment solution of NaNO₃) freezes at a lower temperature than does the pure solvent (deionized water). The higher the
solute concentration (sodium nitrate), freezing point depression of the solution will be greater.
Equation describing the change in freezing point:
ΔT = Kf · b · i.
ΔT - temperature change from pure solvent to solution.
Kf - the molal freezing point depression constant.
b - molality (moles of solute per kilogram of solvent).
i - Van’t Hoff Factor.
First measure freezing point of pure solvent (deionized water). Than make solutions of NaNO₃ with different molality and measure separately their freezing points. Use equation to calculate Kf.
Explanation:
3.Apply the ideal gas law: PV = nRT solving for n. Here you can use the pressure given in atm, but you must choose the 0.0821 atm L/mole K gas constant. Or you can change 4.5 atm to 3420 mm Hg and use the 62.4 mmHg L/mole K gas constant. You must change 500 ml to 0.5 L because both gas constants have units in L, and so the volume must be in liters so it can cancel out. And of course, you must change the temperature to Kelvin.
a. n = (4.5atm)(0.5L)
moliK)(298K) = 0.092 mole (0.0821 atmiL
b. 0.092mol 32g
⎛⎝⎜ ⎞⎠⎟ = 2.9 g
1mol
c. Remember that D = mass
vol so D = 2.9g
0.5L = 5.9 g/L
Answer:
a) 4480L
b) 56L
Explanation:
To answer this question you need to know that Cl2 molecular weight is 71 g/mol and gas volume at NTP is 22.4 L/mol.
a) 14.2 kg of Cl2 in moles will be: 14.2 kg * (1000g/kg) / ( 71g/mol)= 200 mol
The volume of 200 mol of gas in NTP will be: 200 mol * 22.4L/mol= 4480L
b) every mol is made of 6.02 * 10²³ molecules. Then the volume of the gas will be: (15,055×10²³ molecule) / (6.02 * 10²³ molecules/mol) * 22.4 L/mol= 56L
