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3 years ago

What is the mass of 1 centimeter cubes of gold

1 answer:

8 0

The answer is: The change of 1 cc - cm3 ( cubic centimeter ) unit of a gold amount equals = to 19.28 g ( gram ) as the equivalent measure for the same gold type.

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A 0.944 M solution of glucose, C6H12O6, in water has a density of 1.0624 g/mL at 20∘C. What is the concentration of this solutio

____ [38]

Answer:

Mole fraction: 0,0157.

Molality: 0,889m

Mass%: 16%

Explanation:

The units are mole fraction, molality and mass%

Units of mole fraction are moles of glucose per total moles.

Moles of glucose assuming 1L are:

0,944 moles.

Moles of water in 1L are:

1L × (1,0624kg/L) × (1000g / 1kg) × (1mol / 18,02g) = 59,0 moles of water

Mole fraction is: 0,944 moles / (59,0 mol + 0,944mol) = 0,0157

Molality is mole of solute (0,944) per kg of solution (1,0624kg):

0,944mol / 1,0624kg = 0,889m

In mass percent total mass is 1062,4g and mass of 0,944 moles of glucose is:

0,944mol×(180,156g/1mol) = 170g of glucose. Mass%:

170g / 1062,4g ×100 = 16%

I hope it helps!

6 0

3 years ago

Why does a plant have a cell wall and a cell membrane? ASAP Pls have to turn it in at 11:00pm

Aleonysh [2.5K]

Answer:

The cell wall surrounds the plasma membrane and provides the cell tensile strength and protection. ... The cell wall surrounds the plasma membrane of plant cells and provides tensile strength and protection against mechanical and osmotic stress.

hope It Helps U

Please Mark me As brainlist

4 0

3 years ago

H₂ (2) → H. H₂(8) + 2(g) wer

Gre4nikov [31]

The given question is incomplete. The complete question is:

In the chemical reaction: , with 8 grams of and 16 grams of and the reaction goes to completion, what is the excess reactant and how much of that would remain?

A) 6 grams of

B) 7 grams of

C) 8 grams of

D) 12 grams of

E) 14 grams of

Answer: A) 6 grams of $H_2$

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} H_2=\frac{8g}{2g/mol}=4moles$

$\text{Moles of} O_2=\frac{16g}{32g/mol}=0.5moles$

$2H_2(g)+O_2(g)\rightarrow 2H_2O(g)$

According to stoichiometry :

1 moles of $O_2$ require 2 moles of $H_2$

Thus 0.5 moles of $O_2$ will require= $\frac{2}{1}\times 0.5=1.0moles$ of $H_2$

Thus $O_2$ is the limiting reagent as it limits the formation of product and $H_2$ is the excess reagent.

(4.0-1.0) = 3.0 moles of are left unreacted

Mass of remained=

Thus 6.0 g of $H_2$ will remain.

4 0

2 years ago

Why are fossil fuels still the primary way humans harness power

Lubov Fominskaja [6]

Answer:

Fossil fuels are still the number primary way to harness power because we know how to do it very well and it cost less than other any other way to harness energy

Explanation:

3 0

2 years ago

A 250 mL sample of nitrogen (N2) has a pressure of 745 mmHgat 30 ∘C. Find the mass .

Anna71 [15]

The question is incomplete. To complete it you must include the moles of N2 and then you can use the ideal gas law to solve for the mass.

5 0

3 years ago