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trapecia [35]
2 years ago
5

Two laws that protect citizensagainst xenophobia​

Chemistry
1 answer:
Amiraneli [1.4K]2 years ago
3 0
The preservation of human rights in any part of the world plays a key role in maintaining the peace and liberty of its citizens.
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True or False: Mutually beneficial relationships, predator-prey relationships, and competition can happen in different environme
Masja [62]

Answer:

Yes :)

Explanation:

Mutual relationships can include birds cleaning out aligators' teeth, which helps with their hygiene, and gives the bird a meal!

Predator-prey would be a cheetah-antelope.

Competition could be an invasive species :)

8 0
2 years ago
What are the sex cells of the plants that Mendel studied?
guajiro [1.7K]

Answer:

alleles

Explanation:

8 0
3 years ago
Read 2 more answers
What kind of chemical bonds are represented by the product in the following diagram?
katovenus [111]
The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.
4 0
3 years ago
Which section of the reaction represents the reactants
Diano4ka-milaya [45]
A should be the products and D should be the reactants. So D should be the answer.
8 0
3 years ago
Chamber 1 and Chamber 2 have equal volumes of 1.0L and are assumed to be rigid containers. The chambers are connected by a valve
vitfil [10]
1) At tne same temperature and with the same volume, initially the chamber 1 has the dobule of moles of gas  than the chamber 2, so the pressure in the chamber 1 ( call it p1) is the double of the pressure of chamber 2 (p2)

=> p1 = 2 p2

Which is easy to demonstrate using ideal gas equation:

p1 = nRT/V = 2.0 mol * RT / 1 liter

p2 = nRT/V = 1.0 mol * RT / 1 liter

=> p1 / p2 = 2.0 / 1.0 = 2 => p1 = 2 * p2

2) Assuming that when the valve is opened there is not change in temperature, there will be 1.00 + 2.00 moles of gas in a volumen of 2 liters.

So, the pressure in both chambers (which form one same vessel) is:

p = nRT/V = 3.0 mol * RT / 2liter

which compared to the initial pressure in chamber 1, p1, is:

p / p1 = (3/2) / 2 = 3/4 => p = (3/4)p1

So, the answer is that the pressure in the chamber 1 decreases to 3/4 its original pressure.

You can also see how the pressure in chamber 2 changes:

p / p2 = (3/2) / 1 = 3/2, which means that the pressure in the chamber 2 decreases to 3/2 of its original pressure.
5 0
3 years ago
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