Explanation:
The molecules in water is more tightly packed than in ice, so water has greater density than ice.
Answer: skeletal equation : ![Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow NaNO_3(aq)+BaSO_4(s)](https://tex.z-dn.net/?f=Ba%28NO_3%29_2%28aq%29%2BNa_2SO_4%28aq%29%5Crightarrow%20NaNO_3%28aq%29%2BBaSO_4%28s%29)
The products are sodium nitrate and barium sulphate.
balanced equation : ![Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow 2NaNO_3(aq)+BaSO_4(s)](https://tex.z-dn.net/?f=Ba%28NO_3%29_2%28aq%29%2BNa_2SO_4%28aq%29%5Crightarrow%202NaNO_3%28aq%29%2BBaSO_4%28s%29)
Explanation:
A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.
The skeletal equation is:
![Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow NaNO_3(aq)+BaSO_4(s)](https://tex.z-dn.net/?f=Ba%28NO_3%29_2%28aq%29%2BNa_2SO_4%28aq%29%5Crightarrow%20NaNO_3%28aq%29%2BBaSO_4%28s%29)
The balanced chemical equation is:
![Ba(NO_3)_2(aq)+Na_2SO_4(aq)\rightarrow 2NaNO_3(aq)+BaSO_4(s)](https://tex.z-dn.net/?f=Ba%28NO_3%29_2%28aq%29%2BNa_2SO_4%28aq%29%5Crightarrow%202NaNO_3%28aq%29%2BBaSO_4%28s%29)
Don't see how "Little amounts of energy generated " is a cost, more of a less benefit. Harnessing tidal energy will by virtue of conservation of energy take energy out of the tidal system, so B
It takes 31 s for 1.27 M H₃PO₄ to decrease its concentration to 7.0% of its initial value following first-order kinetics.
<h3>What is first-order kinetics?</h3>
First-order kinetics occur when a constant proportion of a reactant disappears per unit time.
Let's consider the following first-order kinetics reaction with a rate constant k = 0.086 s⁻¹.
2 H₃PO₄(aq) = P₂O₅(aq) + 3 H₂O(aq)
Given the initial concentation is [H₃PO₄]₀ = 1.27 M, the concentration representing 7.0% of this value is:
[H₃PO₄] = 7.0% × 1.27 M = 0.089 M
We can calculate the time elapsed (t) using the following expression.
ln ([H₃PO₄]/[H₃PO₄]₀) = - k × t
ln (0.089 M/1.27 M) = - 0.086 s⁻¹ × t
t = 31 s
It takes 31 s for 1.27 M H₃PO₄ to decrease its concentration to 7.0% of its initial value following first-order kinetics.
Learn more about first-order kinetics here: brainly.com/question/18916637
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Answer
is: activation energy of this reaction is 212,01975 kJ/mol.<span>
Arrhenius equation: ln(k</span>₁/k₂) =
Ea/R (1/T₂ - 1/T₁).<span>
k</span>₁
= 0,000643 1/s.<span>
k</span>₂
= 0,00828 1/s.
T₁ = 622 K.
T₂ = 666 K.
R = 8,3145 J/Kmol.
<span>
1/T</span>₁ =
1/622 K = 0,0016 1/K.<span>
1/T</span>₂ =
1/666 K = 0,0015 1/K.<span>
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol ·
(-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol </span>· (-0,0001 1/K).<span>
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>