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Yanka [14]
1 year ago
10

A ball rolls up a hill, going from a speed of 8.09 m/s to a speed of 5.87 m/s in 9.17 seconds. What is its acceleration?

Physics
1 answer:
PilotLPTM [1.2K]1 year ago
4 0

Answer:

Explanation:

Comment

It's actually a deceleration. You should get a negative answer because the ball is slowing down.

Givens

vi = 8.09 m/s

vf = 5.87 m/s

t = 9.17

Formula

a = (vf  - vi) /t                     Substitute the givens into the formula

Solution

a = (5.87 - 8.09)/9.17

Answer

a = - 2.22 m/s^2

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Answer:

(a) 10 m/s

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The center-seeking change in velocity of an object moving in a circle is:
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