If an object is only partially submerged in a fluid, which of the following is true?

12) A neutral atom has two, eight, eight electrons in its first, second, and third energy levels.This information ________.

pentagon [3]

Answer:

C.

Explanation:

Option C

The information given in the question tells us about the number of electrons in an atom and also the number of shells in the atom. So, we will come to know about the atomic number, size and chemical properties of the atom. But we cannot determine atomic mass. Atomic mass is a function of number of neutrons and protons.

3 0

3 years ago

A wave pulse travels down a slinky. The mass of the slinky is m = 0.87 kg and is initially stretched to a length L = 6.8 m. The

Ber [7]

Answer:

1. $v=14.2259\ m.s^{-1}$

2. $F_T=25.8924\ N$

3. $\lambda=29.6373\ m$

Explanation:

Given:

mass of slinky, $m=0.87\ kg$

length of slinky, $L=6.8\ m$

amplitude of wave pulse, $A=0.23\ m$

time taken by the wave pulse to travel down the length, $t=0.478\ s$

frequency of wave pulse, $f=0.48\ Hz=0.48\ s^{-1}$

1.

$\rm Speed\ of\ wave\ pulse=Length\ of\ slinky\div time\ taken\ by\ the\ wave\ to\ travel$

$v=\frac{6.8}{0.478}$

$v=14.2259\ m.s^{-1}$

2.

<em>Now, we find the linear mass density of the slinky.</em>

$\mu=\frac{m}{L}$

$\mu=\frac{0.87}{6.8}\ kg.m^{-1}$

We have the relation involving the tension force as:

$v=\sqrt{\frac{F_T}{\mu} }$

$14.2259=\sqrt{\frac{F_T}{\frac{0.87}{6.8}} }$

$202.3774=F_T\times \frac{6.8}{0.87}$

$F_T=25.8924\ N$

3.

We have the relation for wavelength as:

$\lambda=\frac{v}{f}$

$\lambda=\frac{14.2259}{0.48}$

$\lambda=29.6373\ m$

8 0

3 years ago

A watermelon is dropped from the top of a 80m tall building. We want to find the velocity of the watermelon after it falls for 1

White raven [17]

Answer:

$v_f = v_i + at$

$v_f = 13.23 m/s$

Explanation:

Height Of the watermelon when it is dropped is given as

$h = 80 m$

time of fall under gravity

$t = 1.35 s$

now if water melon start from rest then we have

$v_i = 0$

acceleration due to gravity for watermelon

$a = 9.81 m/s^2$

now we need to find the final speed of watermelon

$v_f = v_i + at$

so we will have

$v_f = 0 + (9.81)(1.35)$

$v_f = 13.23 m/s$

7 0

3 years ago

When the temperature of the air is 50°C, the velocity of a sound wave traveling through the air is approximately?

noname [10]

The answer is:

C. 361 m/s

The explanation:

To calculate the speed of sound at a given temperature (50°C) we are going to use this formula:

v = 331 + 0.6T

when V is the velocity

and T is the temperature = 50°C

by substitution:

v = 331 + 0.6(50)

v = 361 m/s

So, The correct answer is C.

because of the variation of the motion of the molecules of air with change of temperature so, the velocity (V) of the sound in the air is change with temperature.

5 0

3 years ago

Read 2 more answers

True or false, russian twists focus to strengthen the latissimus dorsi

Oliga [24]

The answer is true hope that helped!!

5 0

3 years ago

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