Answer:
friction
Explanation:
Her brakes will squeak and possibly slide or skid on concrete due to her brakes.
BUT it really depends on the condition of the wheels. Now it matters on the surface as well. Has the road been eroded? what has happened with her brakes? and what texture are the wheels? can seismic waves travel through them?
Answer:
Explanation:
Width of central diffraction peak is given by the following expression
Width of central diffraction peak= 2 λ D/ d₁
where d₁ is width of slit and D is screen distance and λ is wave length.
Width of other fringes become half , that is each of secondary diffraction fringe is equal to
λ D/ d₁
Width of central interference peak is given by the following expression
Width of each of bright fringe = λ D/ d₂
where d₂ is width of slit and D is screen distance and λ is wave length.
Now given that the central diffraction peak contains 13 interference fringes
so ( 2 λ D/ d₁) / λ D/ d₂ = 13
then ( λ D/ d₁) / λ D/ d₂ = 13 / 2
= 6.5
no of fringes contained within each secondary diffraction peak = 6.5
Explanation:
Given that,
Mass of the hamster, m = 0.139 kg
Diameter of the wheel, d = 20.8 cm
Radius, r = 10.4 m
Frequency of the wheel, f = 1 Hz
Time, t = 0.823 s
(a) There exist a relationship between the tangential and angular acceleration of the wheel. It is given by :

Since, 




(b) In radial direction, applying the second law of motion as :

a is the radial acceleration, 








Hence, this is the required solution.
7.5m/s (2.5 x 3) c = frequency x wavelength