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KengaRu [80]
1 year ago
14

55. Write the shortened notation for the ion symbol next to each element given below. A.) Calcium loses 2 negative electronsB.)

Chlorine gains 1 negative electronsC.) Hydrogen gains 1 negative electron
Physics
1 answer:
Eddi Din [679]1 year ago
6 0

We are asked to write shortened notation for the ion symbol next to each element given below.

Convention:

First of all, write the shortened notation of the element.

The superscript (at the top) is the number of charges on the ion and also a + sign for a positive ion and - sign for a negative ion.

When an atom loses an electron then the charge is positive (+).

When an atom gains an electron then the charge is negative (-)

A.) Calcium loses 2 negative electrons

Since it loses 2 electrons it will have 2+ superscript.

Calcium has an atomic number of 20 (the number of protons)

_{20}Ca^{2+}

B.) Chlorine gains 1 negative electron

Since it gains 1 electron it will have - superscript (we don't write 1 when the charge is 1)

Chlorine has an atomic number of 17 (the number of protons)

_{17}Cl^-

C.) Hydrogen gains 1 negative electron

Since it gains 1 electron it will have - superscript

Hydrogen has an atomic number of 1 (the number of protons)

_1H^-

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Ronch [10]

Answer:

1. G.P.E = 24 J

2. center of mass

Explanation:

Given the following data;

Mass = 2kg

Height, h = 1.2m

Acceleration due to gravity = 9.8 N/kg or m/s².

To find the gravitational potential energy;

Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.

Mathematically, gravitational potential energy is given by the formula;

G.P.E = mgh

Where;

  • G.P.E represents potential energy measured in Joules.
  • m represents the mass of an object.
  • g represents acceleration due to gravity measured in meters per seconds square.
  • h represents the height measured in meters.

Substituting into the formula, we have;

G.P.E = 2*1.2*9.8

G.P.E = 23.52 to 2 S.F = 24 Joules.

Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.

6 0
2 years ago
6th grade science I mark as brainliest
Mila [183]

Answer:

8. organelle

Explanation:

9. Epithelial tissue

am i correct?

8 0
3 years ago
A 62kg box is lifted 12 meters off the ground. How much work is done?
Temka [501]

Answer: 7291.2 joules

Explanation:

Work is done when force is applied on an object over a distance.

Thus, Workdone = Force X distance

Since Distance moved by box = 12 metres

mass of box = 62kg

Acceleration due to gravity when box was lifted is represented by g = 9.8m/s^2

Recall that Force = Mass x acceleration due to gravity

i.e Force = 62kg x 9.8m/s^2

= 607.6 Newton

So, Workdone = Force X Distance

Workdone = 607.6 Newton X 12 metres

Workdone = 7291.2 joules

Thus, 7291.2 joules of work was done.

4 0
3 years ago
In 1993 Ileana Salvador of Italy walked 3.0km in under 12min. Suppose that during her walk Salvador is observed to steadily incr
padilas [110]

The distance covered is 115 m

Explanation:

The motion of Ileana is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the distance covered

u is the initiaal velocity

v is the final velocity

t is the time elapsed

In this problem, we have:

u = 4.20 m/s

v = 5.00 m/s

t = 25.0 s

Therefore, we can re-arrange the equation to find the distance covered:

s=(\frac{4.20+5.00}{2})(25.0)=115 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

5 0
3 years ago
Un avión da "una vuelta mortal" de radio R = 500 m con una celeridad constante v = 360 km/h. Halla la fuerza ejercida por el asi
Airida [17]

Answer:

1400 N

Explanation:

Verá, durante el salto mortal, el piloto se mueve en una trayectoria circular y la fuerza que actúa sobre él es una fuerza centrípeta.

Sea la fuerza centrípeta F, la masa del piloto (m) = 70 Kg, el radio (r) = 500 my la velocidad (v) = 360 km / hr * 1000/3600 = 100 m / s

F = mv ^ 2 / r

F = 70 * (100) ^ 2/500

F = 1400 N

8 0
3 years ago
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