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-BARSIC- [3]
1 year ago
12

a canon is firing horizontally from the high wall of a castle located in the midst of a flat plain. if i drop a canon ball from

the wall where the canon is located, it it takes 3 sec to hit the ground. what do i need to know to find how far away from the wall the canon balls will land when fired from the canon? the exit velocity from the canon, only. no further information is needed. the height of the wall, only.
Physics
1 answer:
dsp731 year ago
3 0

D=44.13, Horizontal velocity is unimportant. The time it takes the cannon ball to fall to the ground is the key to determining the height of the cliff. where  that cannon is present.

The speed of any projectile travelling along a Horizontal velocity is known as the horizontal velocity. When a particle or object is launched into the air at an angle other than 90 degrees, it moves along the trajectory path and changes the shape of the curve to a parabolic one.

the speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples. This is called acceleration.

Distance to the ground is d = 1/2gt^2,

where g is the acceleration rate of gravity (9.80665 m/s^2)

and t = 3 secs.

d = .5×9.80665×9 = 44.13 m.

Learn more about horizontal velocity here

brainly.com/question/18084516

#SPJ4

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Firstly, let's convert the velocities in km/hr to m/s
32*1000/3600=8.89m/s
54*1000/3600=15m/s
From the formula, acceleration=V-U/t
15-8.89/8=0.76m/s²
hope this helps.
7 0
3 years ago
a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro
finlep [7]

Answer:

\theta=53.13^o

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

V_x=V_{ox}=V_ocos\theta

V_y=V_{oy}-gt=V_osin\theta-gt

x=V_{ox}t

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}

\displaystyle y_{max}=\frac{V_{oy}^2}{2g}

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

x_{max}=3y_{max}

\displaystyle \frac{2V_{ox}V_{oy}}{g}=3\frac{V_{oy}^2}{2g}

Using the formulas for V_{ox}, V_{oy}:

\displaystyle \frac{2V_{o}cos\theta V_{o}sin\theta}{g}=3\frac{V_{o}^2sin^2\theta}{2g}

Simplifying

4cos\theta sin\theta=3sin^2\theta

Dividing by sin\theta

4cos\theta=3sin\theta

Rearranging

tan\theta=\frac{4}{3}

\theta=arctan\frac{4}{3}

\theta=53.13^o

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Answer:

1

Explanation:

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Please answer this question brainliest ko promise
Paul [167]

Answer:

The language you typed into the bar is Filipinio and can be translated to "what sources of information do you have in your home and how can it help?"

The sources of information most people have in their home are Books, Encyclopedias, Magazines, Databases, Newspapers, Library Catalog, Internet. Hope this helped!

7 0
3 years ago
An object with more mass has more kinetic energy than an object with less mass, if both objects are moving ____.
suter [353]

An object with more mass has more kinetic energy than an object with less mass, if both objects are moving at the same speed. <em>(c)</em>

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