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sergij07 [2.7K]
3 years ago
15

Question 7 (1 point)

Physics
1 answer:
Temka [501]3 years ago
4 0

Answer:

Forms over water, warm humid air mass, it's a polar air mass

Explanation: I think that's right sorry if it's not..

GL! :)

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Which statement describes a controlled experiment?
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Answer:

In a controlled experiment, an independent variable (the cause) is systematically manipulated and the dependent variable (the effect) is measured; any extraneous variables are controlled. The researcher can operationalize (i.e. define) the variables being studied so they can be objectivity measured.

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Kepler's 3 laws with formula centerpital<br> forces
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Answer:

Kepler's Third Law

T = 2 π r 3 G M E . T = 2 π r 3 G M E . For an ellipse, recall that the semi-major axis is one-half the sum of the perihelion and the aphelion. For a circular orbit, the semi-major axis (a) is the same as the radius for the orbit.

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Assuming no friction, how does the initial gravitational potential energy of
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a) They are the same.

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A car, starting from the origin, travels 4 km east and then 7 km west. What is the traveled distance of the car from the initial
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3 0
3 years ago
The half-life of nickel-63 is 100 years. If a sample of nickel-63 decays until 6.25% of the original sample remains, how much ti
a_sh-v [17]

Answer:

400 years

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The equation that describes the decay of a radioactive sample is:

m(t)=m_0 (\frac{1}{2})^{t/t_{1/2}} (1)

where

m(t) is the amount of sample left at time t

m_0 is the initial amount of the sample

t_{1/2} is the half-life, which is the time taken for the sample to halve

In this problem we have:

t_{1/2}=100 y is the half-life of Nickel-63

After a time t, the amount of sample left is 6.25% of the original one, which means that

\frac{m(t)}{m_0}=\frac{6.25}{100}

So we can rewrite the equation (1) and solving for t to find the time:

\frac{6.25}{100}=(\frac{1}{2})^{t/t_{1/2}}\\\rightarrow \frac{t}{t_{1/2}}=4\\t=4t_{1/2}=4(100)=400 y

5 0
3 years ago
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