Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:

The minimun wall thickness:

Answer:
Positive
Explanation:
The leaves will diverge further: The positive charge on the leaves has increased further. This occurs when positive charge is produced on the leaves by the charged object. This is quite possible only when the object is positively charged.
Answer:
the answer is
B)It was the first planet located through mathematical calculations
Answer:
D. 12 cm
Explanation:
A node is a point on a standing wave that does not vibrate.
The nodes of a standing wave are shown in the following sketch.
The red dots are the nodes of the standing wave.
It is observed that the distance between two adjacent nodes is half the wavelength of the wave.
Therefore, if the wavelength of the wave is 24 cm, then the distance from one node to the net must be 24 / 2 = 12 cm.
Hence, choice D is the correct answer.