The linear speed of the basketball at the bottom in m/s is 37.41 m/s.
The mechanical energy basket ball is conserved and the basket ball starts from rest. and roll down a hill of height 70m.
If mechanical energy is conserved,
Potential energy at top + kinetic energy at top = potential energy at bottom + kinetic energy at bottom.
At bottom, there is no potential energy, and at top, there is no kinetic energy.
Potential energy at top = kinetic energy at bottom.
Mgh = 1/2Mv²
M is the mass of the basketball,
v is the linear speed at the bottom,
h is the height of the ball.
Putting values,
v = √(2gh)
v = √(2x10x70)
v = 37.41m/s.
The speed of the basketball at the bottom is 37.41 /s.
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