Question

a basketball (hollow sphere) starts from rest and rolls down a hill without slipping. the hill is 70 meter high. total mechanical energy is conserved. find the linear speed of the basketball at the bottom in m/s.

Answer 1

The linear speed of the basketball at the bottom in m/s is 37.41 m/s.

The mechanical energy basket ball is conserved and the basket ball starts from rest. and roll down a hill of height 70m.

If mechanical energy is conserved,

Potential energy at top + kinetic energy at top = potential energy at bottom + kinetic energy at bottom.

At bottom, there is no potential energy, and at top, there is no kinetic energy.

Potential energy at top = kinetic energy at bottom.

Mgh = 1/2Mv²

M is the mass of the basketball,

v is the linear speed at the bottom,

h is the height of the ball.

Putting values,

v = √(2gh)

v = √(2x10x70)

v = 37.41m/s.

The speed of the basketball at the bottom is 37.41 /s.

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