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Dahasolnce [82]
1 year ago
11

by doing a nuclear diffraction experiment, you measure the de broglie wavelength of a proton to be 8.29 fm. (a) what is the spee

d of the proton? (b) through what potential difference must it be accelerated to achieve that speed?
Physics
1 answer:
Irina18 [472]1 year ago
6 0

By the de Broglie wavelength equation, the speed of proton is <u>0.47 × </u>10^{8}<u> m/s</u>.

λ = h / mv

λ = wavelength, given = 8.29 fm

h = plank's constant, given = 6.626 × 10^{-34}

m = mass, given = 1.672 × 10^{-27} kg

v = velocity

Now, v = h / mλ

Put the values in formula,  v = h / mλ

v = 0.47 × 10^{8} m/s

Therefore, the speed of proton is<u> 0.47 × </u>10^{8}<u> m/s</u>.

Learn more about de Broglie wavelength here:- brainly.com/question/15330461

#SPJ4

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