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2 years ago

What is the difference between a single-model production line and a mixed-model production line?

1 answer:

6 0

The unique model production line is responsible for producing identical pieces. For this purpose the balancing of the assembly line is only responsible for assembling a model throughout the line.

This is a considerable difference compared to the mixed model assembly line where many models are assembled during the same production line, that is, it produces parts or products that have slight changes accommodated in them, with slight variations in their model or products of soft variety

The choice of the type of production depends on the type of company and its own demand, always prioritizing the efficiency in the operation. Generally, the mixed model tends to be chosen when demand is very large and customer demand is required to be met. In others it is considered a plant model in which half of the line is mixed and the other one is the only model in order to keep the efficiency balanced.

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Ordan has _ 5 8 can of green paint and _ 3 6 can of blue paint. If the cans are the same size, does Jordan have more green paint

Morgarella [4.7K]

Answer:

Jordan has more green paints

Explanation:

Given

$Green = \frac{5}{8}$

$Blue = \frac{3}{6}$

Required

Which paint does he have more?

For better understanding, it's better to convert both measurements to decimal.

For the green paint:

$Green = \frac{5}{8}$

$Green = 0.625$

For the blue paint:

$Blue = \frac{3}{6}$

$Blue = 0.5$

By comparison:

$0.625 > 0.5$

<em>This means that Jordan has more green paints</em>

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2 years ago

A cooling system load is 96,000 BTUh sensible. How much chilled air is required to satisfy the load if the system is designed fo

Natalija [7]

Answer:

For $20^{\circ}$ - 5.556 lb/s

For $15^{\circ}$ - 7.4047 lb/s

Solution:

As per the question:

System Load = 96000 Btuh

Temperature, T = $20^{\circ}$

Temperature rise, T' = $15^{\circ}$

Now,

The system load is taken to be at constant pressure, then:

Specific heat of air, $C_{p} = 0.24 btu/lb ^{\circ}F$

Now, for a rise of $20^{\circ}$ in temeprature:

$\dot{m}C_{p}\Delta T = 96000$

$\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 20} = 20000 lb/h = \frac{20000}{3600} = 5.556 lb/s$

Now, for $15^{\circ}$ :

$\dot{m}C_{p}\Delta T = 96000$

$\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 15} = 26666.667 lb/h = \frac{26666.667}{3600} = 7.4074 lb/s$

4 0

2 years ago

For a steel alloy it has been determined that a carburizing heat treatment of 11-h duration will raise the carbon concentration

Jobisdone [24]

Answer:

Time =t2=58.4 h

Explanation:

Since temperature is the same hence using condition

x^2/Dt=constant

where t is the time as temperature so D also remains constant

hence

x^2/t=constant

2.3^2/11=5.3^2/t2

time=t^2=58.4 h

4 0

2 years ago

Where are the ar manufacturers not fitting the engine in the high end sport cars

fomenos

Answer:

it depends on the but i would recommend check in the front next to the turbo intake.

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2 years ago

If they opened up the International Space Station to tourism, would you go? Why? answer in 2 sentences

Arlecino [84]

Personally, I would go to the space station. The space station has extreme different levels of technology and abilities, plus who doesn’t want to go to space.

6 0

3 years ago

Read 2 more answers