Answer:
Gs = 2.647
e = 0.7986
Explanation:
We know that moist unit weight of soil is given as
![\gamma_m \ or\ bulk\ density = \frac{(Gs+Se)\times \gamma_w}{(1+e)}](https://tex.z-dn.net/?f=%5Cgamma_m%20%5C%20or%5C%20bulk%5C%20density%20%3D%20%5Cfrac%7B%28Gs%2BSe%29%5Ctimes%20%5Cgamma_w%7D%7B%281%2Be%29%7D)
where,
= moist unit weight of the soil
Gs = specific gravity of the soil
S = degree of saturation
e = void ratio
= unit weight of water = 9.81 kN/m3
From data given we know that:
At 50% saturation,![\gamma_m = 16.62 kN/m3](https://tex.z-dn.net/?f=%20%5Cgamma_m%20%3D%2016.62%20kN%2Fm3)
puttng all value to get Gs value;
![16.62= \frac{(Gs+0.5*e)\timees 9.81}{(1+e)}](https://tex.z-dn.net/?f=16.62%3D%20%5Cfrac%7B%28Gs%2B0.5%2Ae%29%5Ctimees%209.81%7D%7B%281%2Be%29%7D)
Gs - 1.194*e = 1.694 .........(1)
for saturaion 75%, unit weight = 17.71 KN/m3
![17.71 = \frac{(Gs+0.75*e)\times 9.81}{(1+e)}](https://tex.z-dn.net/?f=17.71%20%3D%20%5Cfrac%7B%28Gs%2B0.75%2Ae%29%5Ctimes%209.81%7D%7B%281%2Be%29%7D)
Gs - 1.055*e = 1.805 .........(2)
solving both equations (1) and (2), we obtained;
Gs = 2.647
e = 0.7986
Answer:
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The designers suggest that speech recognition allows for spoken interaction or conversation and spoken prompts or commands.
Explanation:
The speech recognition is used when the user has physical impairments and hands are busy, eyes are occupied and the user cannot read.
We can save time with the usage of speech recognition system. The users are knowledgeable based on the actions available.
The problems faced in speech recognition system are in the noisy environment it has bad microphones and the commands should be learned and remembered.
The other obstacle is error correction is time consuming. the speech production has slow space to speech output provides privacy in public spaces. The disadvantage is it contains large amount of information.
Answer:
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Answer:
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