If the echo is detected 2 seconds after the ping is transmitted,
then the sound has traveled
(2 sec) x (1533 meter/sec) = 3,066 meters.
But the sound had to travel down from the boat to the bottom, then
get reflected, then travel up from the bottom to the boat. So the
sound actually traveled a distance equal to double the depth.
The depth is (1/2) (3,066 meters) = 1,533 meters .
(about 5,030 feet)
Answer:
w = w₀ M / (M + 2m)
Explanation:
This exercise can be solved using the concepts of conservation of angular momentum
L = I w
Let's write in angular momentum in two points
Initial. Before impact
L₀ = I w₀
Final. After the rock has stuck
= I w + (m r²) w
The system is formed by the disk and the rock, so that the forces and moments during the crash are internal and the angular momentum is preserved
L₀ =
I w₀ = (I + m r²) w
w = w₀ I / (I + m r²)
The roundabout is a disk so its moment of inertia is
I = ½ M r²
w = w₀ ½ Mr² / (½ M r² + mr²)
w = w₀ ½ M / (½ M + m)
w = w₀ ½ M2 / (M + 2m)
w = w₀ M / (M + 2m)
Answer:
If its not functioning properly then it is probably broken
Explanation:
Answer:
1438.4 N
Explanation:
Applying,
F = kqq'/r²................... Equation 1
Where F = Electrostatic force on the balloons, k = coulomb's constant, q = charge on the first balloon, q' = charge on the second balloon, r = distance between the two ballons.
From the question,
Given: q = q' = 4.0×10⁻⁵ C, r = 0.1 m
Constant: k = 8.99×10⁹ Nm²/C²
Substitute these values into equation 1
F = ( 4.0×10⁻⁵×4.0×10⁻⁵×8.99×10⁹)/0.1²
F = 14.384/0.01
F = 1438.4 N
Answer:
An image can be seen in the mirror because the light reflected from an object falls on the mirror and it is reflected.