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ivolga24 [154]
3 years ago
11

What happens to water particles when they are heated? Select the box if the sentence is true. Leave the box blank if it is NOT.

*
5 points
The speed of the water particles increases.
The size of the water particles increases.
The number of water particles increases.
The space between the water particles increases.
The number of collisions between water particles increases.
Chemistry
1 answer:
mina [271]3 years ago
7 0

Answer:

The speed of the water particles increases.

The number of collisions between water particles increases.

Explanation:

When water particles are heated, the speed of the particles increases and the number of collisions between the water particles also increases.

  • Heating increases the thermal energy of the system
  • When water particles gain more thermal energy, their average speed increases drastically.
  • Also, the frequency of collisions increases due to the gain in thermal energy of the system.
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An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 5.00g of this compound produced 7.33g of
Olegator [25]
A combustion reaction involves an organic compound reacted with oxygen. The general chemical equation is as follows:
<span>
Organic Compound + Oxygen = CO2 + H2O

</span><span>To calculate the amount of C present in the original sample, we use the values given and assume that there is complete combustion that is happening.
</span><span>
7.33 g CO2 ( 1 mol CO2 / 44.01 g CO2)(1 mol C / 1 mol CO2) = 0.167 mol C

Therefore, 0.167 mol of C was originally in the sample.</span>
8 0
3 years ago
Read 2 more answers
Calculate the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L.
Aleonysh [2.5K]

Answer: 15.5^0C

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.987 atm

V = Volume of gas = 12 L

n = number of moles = 0.50

R = gas constant =0.0821Latm/Kmol

T =temperature =  ?

T=\frac{PV}{nR}

T=\frac{0.987atm\times 12L}{0.0820 L atm/K mol\times 0.50mol}=288.5K=(288.5-273)^0C=15.5^0C

Thus the temperature of a 0.50 mol sample of a gas at 0.987 atm and a volume of 12 L is 15.5^0C

8 0
3 years ago
If you know the mass of an object you can calculate its weight with the formula
Vikki [24]
Answer: True

The formula of weight is w = mg, where m is the mass and g is the acceleration of gravity. If you want to calculate an object's weight, you need to know the two components: mass and gravity. 

You only need to know the mass of the object because the acceleration of gravity is ALWAYS (assuming the object is on Earth) 9.8 m/s^2. 
3 0
3 years ago
Boron has two naturally occurring isotopes; B-10 with a mass of 10.01 amu and a natural abundance of 20.00%, and B-11 with a mas
balandron [24]

Atomic mass of boron = 10.81

<h3>What are Isotopes?</h3>

Isotopes are variants of a particular element in which they have the same number of protons but differ in the number of neutrons in the atom.

So, here as we said we have isotopes which weigh 10.01 and 11.01.

Given,

relative abundance of B-10 = 10.1 amu

relative abundance of B- 11 = 11.01 amu

percentage of B-10 = 20%

percentage of B-11 = 80%

Then the relative atomic mass depends upon the relative abundance of various isotopes of that particular element. Suppose an element consists of two isotopes and average atomic mass is equal to

(Relativeabundance(1)×Atomicmass(1)+Relativeabundance(2)×Atomicmass(2)) / (Relativeabundance(1)+Relativeabundance(2))

Atomic mass of boron = (20 × 10.01 + 80 × 11.01) / (80 + 20 )

= 1081/100

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To learn more about atomic mass from the given link

brainly.com/question/3187640

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8 0
2 years ago
A gas initial volume and pressure is 5m^3 and 101320 Pa and allows to expand up to 12m^3 then what is the final pressure?
Anton [14]

Answer:

New pressure = 42216.66 Pa

Explanation:

Given that,

Initial volume, V₁ = 5 m³

Final pressure, P₁ = 101320 Pa

Final volume, V₂ = 12 m³

We need to find the final pressure of the gas. We know that the relation between pressure and volume is given by :

P\propto \dfrac{1}{V}\\\\P_1V_1=P_2V_2\\\\P_2=\dfrac{P_1V_1}{V_2}\\\\P_2=\dfrac{101320 \times 5}{12}\\\\P_2=42216.67\ Pa

So, the new pressure is equal to 42216.66 Pa.

6 0
3 years ago
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