Well, for
her questionnaire she could use and create questions or queries that are
obviously related to her hypothesis or study.
These
could be done in a likert type of scale.
<span><span>
1.
</span>I read most often.
</span>
<span><span>a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
<span><span>
2.
</span>When I read my books its takes me 24 hours a day</span>
<span><span>
a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
<span><span>
3.
</span>When I start reading I can’t stop</span>
<span><span>
a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
Answer:
-24/5
Step-by-step explanation:
The solution to the problem is as follows:
cscx < 0 means 1/sinx < 0, or sinx < 0.
sinx = -3/5 because you're dealing with a 3-4-5 triangle, and we established
sinx is negative.
sin2x = 2sinxcosx = 2*-3/5*4/5 = -24/25
cos(2x) = cos^2(x) - sin^2(x) = 16/25 - 9/25 = 5/25 = 1/5
tan2x = sin2x / cos2x = -24/5
That'd be a total of 6 km east and 4 km north.
The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.
However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:
sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km
First you will use the slope formula:
M= Rise/Run = Y2-Y1/X2-X1
(0,13) (-4,10)
10-13
——— = -3/4 = 3/4
-4-0.
