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Maksim231197 [3]
1 year ago
6

a substance has a vapor pressure of 0.2020 atm at 261.5 k. if its heat of vaporization is 20.94 kj/mol, calculate its vapor pres

sure at 240.9 k.
Chemistry
1 answer:
Arisa [49]1 year ago
7 0

The vapor pressure at the new temperature can be obtained as  0.074 atm.

<h3>What is the vapor pressure?</h3>

The term vapor pressure has to do with the pressure that accumulates owing to the fact that some of the liquid is leaving the solution and gets to the top of the container.

Now we have the formula;

ln(P2/P1) = -ΔHvap/R(1/T2 - 1/T1)

P2 = final pressure

P1 = initial pressure

ΔHvap = Enthalpy of vaporization

T2 = final  temperature

T1 = initial temperature

ln(P2/0.2020) = -20.94 * 10^3/8.314(1/240.9 - 1/261.5)

ln(P2/0.2020) = -2518.6(0.0042 - 0.0038)

ln(P2/0.2020) = -1.00744

Taking the exponential of both sides;

P2/0.2020 = e^-1.00744

P2 =  e^-1.00744 * 0.2020

P2 = 0.074 atm

Learn more about vapor pressure:brainly.com/question/11864750

#SPJ1

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