Question

A 68 kg object, starting from rest, travels from point A to point B at a rate of 30 m/s in 2 hours. What is the applied force on the object?

Answer 1

Answer:

$\huge\boxed{\sf F = 0.28\ N}$

Explanation:

Given Data:

Mass = m = 68 kg

Velocity = v = 30 m/s

Time = 2 hours = 2 × 60 × 60 = 7200 s

Required:

Force = F = ?

Formula to be used:

$\displaystyle F = \frac{mv}{t}$

Solution:

$\displaystyle F = \frac{(68)(30)}{7200} \\\\F = \frac{2040}{7200} \\\\F = 0.28 N\\\\\rule[225]{225}{2}$