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Ray Of Light [21]
1 year ago
6

Explain why Nitrogen -17 is unstable

Chemistry
1 answer:
Yuri [45]1 year ago
4 0
Has only 7 electrons so it want to bond with other elements so its very reactive and unstable. Hope this helps
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Cellular respiration uses glucose and oxygen, which have high levels of free energy, and releases carbon dioxide and water, whic
Alja [10]

Answer: Cellular respiration is spontaneous and exergonic. The energy released from the glucose is stored in ATP molelcules.

Explanation:

Spontaneous reactions have an increase in entropy (level of disorder) and a decrease in enthalpy (total energy). Cellular respiration goes from a more ordered state (one molecule of glucose) to a more disordered state (several molecules of CO2), and goes from a state with a lot of free energy to one with much less free energy. As a result, respiration is a spontaneous process.

As free energy from the glucose is released as ATP molecules during oxidation, the reaction is exergonic.

4 0
3 years ago
Read 2 more answers
The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37°C, the r
rodikova [14]

Answer:

E₁ ≅ 28.96 kJ/mol

Explanation:

Given that:

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol,

Let the activation energy for a catalyzed biochemical reaction = E₁

E₁ = ??? (unknown)

Let the activation energy for an uncatalyzed biochemical reaction = E₂

E₂ = 50.0 kJ/mol

    = 50,000 J/mol

Temperature (T) = 37°C

= (37+273.15)K

= 310.15K

Rate constant (R) = 8.314 J/mol/k

Also, let the constant rate for the catalyzed biochemical reaction = K₁

let the constant rate for the uncatalyzed biochemical reaction = K₂

If the  rate constant for the reaction increases by a factor of 3.50 × 10³ as compared with the uncatalyzed reaction, That implies that:

K₁ = 3.50 × 10³

K₂ = 1

Now, to calculate the activation energy for the catalyzed reaction going by the following above parameter;

we can use the formula for Arrhenius equation;

K=Ae^{\frac{-E}{RT}}

If K_1=Ae^{\frac{-E_1}{RT}} -------equation 1     &

K_2=Ae^{\frac{-E_2}{RT}} -------equation 2

\frac{K_1}{K_2} = e^{\frac{-E_1-E_2}{RT}

E_1= E_2-RT*In(\frac{K_1}{K_2})

E_1= 50,000-8.314*310.15*In(\frac{3.50*10^3}{1})

E_1 = 28957.39292  J/mol

E₁ ≅ 28.96 kJ/mol

∴ the activation energy for a catalyzed biochemical reaction (E₁) = 28.96 kJ/mol

8 0
3 years ago
Gas chromatography can be useful in determining what about paint?
dexar [7]
Gas chromatography is a type of <span>chromatography that is usually used in analytic chemistry in order to analyze and separate the compounds that can be vaporized without decomposition.

Based on this:
</span><span>Gas chromatography can be useful in determining the chemical composition of paint.</span>
4 0
3 years ago
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Match each processes with the correct transfer of energy.
sveticcg [70]

freezing-energy lost (exothermic)

sublimation-energy gain (endothermic)

evaporation- energy gain(endothermic)

Melting- energy gain(endothermic)

deposition- energy lost(exothermic)

condensation-energy lost(exothermic)

7 0
3 years ago
The number placed in front of a formula is called a coefficient. the small number within a chemical equation formula is called a
Rufina [12.5K]
Because coefficients numbers make the elements to be stable.
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3 years ago
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