Answer:
<u>O-H stretch signal at 3300 cm-1</u>
Explanation:
In this question, we can start with the <u>reaction mechanism</u> for the synthesis of Nerolin. We have to start with naphthalen-2-ol adding NaOH we can produce the alkoxide. Then this alkoxide can react by an <u>Sn2 reaction</u> with bromomethane to produce Nerolin (see figure 1).
In the starting molecule (naphthalen-2-ol) we have an <u>"OH" group</u>. Therefore we will have an <u>O-H stretch signal</u> around 3300 cm^-1. The alcohol signals are very broad and very intense, so this will be the main signal for the initial molecule. In the final product, we dont have the "OH" therefore this signal will disappear (see figure 2).
I hope it helps!
Answer:
For the first reaction the reagents are: MgCl2 and Na2CO3
For the second reaction the reagents are: Na2HPO4 and CaCl2
Explanation:
Precipitation reactions lie in the production of a compound that is not soluble, which is called a precipitate, this precipitate is produced when two different solutions are combined, each of which will contribute an ion for the formation of the precipitate. In the first reaction you have:
MgCl2 + Na2CO3 = MgCO3 + 2 NaCl
Type of reaction: double displacement
The second reaction is as follows:
4Na2HPO4 + 3CaCl2 → Ca3 (PO4) 2 + 2NaH2PO4 + 6NaCl
It is the reaction of sodium hydrochlorophosphate and calcium chloride
Answer:
39.72 g
Explanation:
Given data:
Mass of CsF = 15.2 g
Mass of XeF₆ = 260 g
Mass of Cs[XeF₇] = ?
Solution:
Chemical reaction:
CsF + XeF₆ → Cs[XeF₇]
Number of moles of CsF:
Number of moles = mass/ molar mass
Number of moles = 15.2 g/151.9 g/mol
Number of moles = 0.1 mol
Number of moles of XeF₆ :
Number of moles = mass/ molar mass
Number of moles = 260 g/245.28 g/mol
Number of moles = 1.06 mol
Now we will compare the moles of Cs[XeF₇] with both reactants.
CsF : Cs[XeF₇]
1 : 1
0.1 : 0.1
XeF₆ : Cs[XeF₇]
1 : 1
1.06 ; 1.06
Number of moles of Cs[XeF₇] produce by CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].
Mass of Cs[XeF₇]:
Mass = number of moles × molar mass
Mass = 0.1 mol × 397.2 g/mol
Mass = 39.72 g
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