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sesenic [268]
1 year ago
14

If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the

spring when it is stretched 10 m?
Physics
1 answer:
lys-0071 [83]1 year ago
5 0

ANSWER:

250 J

STEP-BY-STEP EXPLANATION:

F = 20N is required to stretch the spring by 4 meters

We know that the force is equal to:

F=k\cdot x

We solve for k (spring constant):

k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}

The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:

\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}

The work required is 250 joules.

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He traveled 9km

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3 years ago
If your chunk of gold weighed 1 N in which case would you have the largest mass of gold?
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Thought-provoking, even.

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"Local gravity" is the denominator of the fraction, so the fraction
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If somebody offers you 1 chunk of gold that weighs 1 Newton,
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   "Fine !  Great !  Golly gee, that's sure generous of you.  
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The local acceleration of gravity on Pluto is  0.62 m/s² ,
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KengaRu [80]

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<h3>What is density of an object?</h3>

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To determine the density of an object therefore, the physical characteristics of mass and the volume of the object are measured.

The mass of the object is obtained using a scale or a balance.

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#SPJ1

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