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finlep [7]
1 year ago
14

Concentrated hydrochloric acid is approximately 12.2 M. If a student needs to prepare 250. mL of 0.500 M hydrochloric acid, what

volume (mL) of concentrated acid is needed?
Chemistry
1 answer:
Mice21 [21]1 year ago
5 0
Answer:
Would it be 10.2 mL? I used the formula M1V1=M2V2
Explanation:
I think the person that asked it correct

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A change resulting in one or more new substances being formed is a?
dem82 [27]

Answer:

C. Chemical change

Explanation:

A physical change is where something is changed but it doesnt affect the build up of the chemical. For example, if you broke sticks and threw them on the ground, that would be a physical change because the change is happening to the physical being of the object and not its chemical buildup. However, if you lit those sticks on fire, that would be considered a chemical change because you end up with two substances, ash and the remnants of the stick. A nuclear reaction would result in something blowing up so its not that. And a physical property is like what it looks like or how it smells. Hope I helped you!

3 0
2 years ago
What represents a community?<br> pond<br> B<br> a snail<br> snails<br> D snails, guppies and plants
OLga [1]

D snails, guppies and plants. The community should be diverse and have lots of biodiversity.

7 0
2 years ago
What is the oxidation state of an individual nitrogen atom in nh2oh?
Anna [14]
Give up I'm going to.
4 0
3 years ago
A gas occupies 14.3 liters at a pressure of 45.0 mm Hg. What is the volume when the pressure is increased to
Simora [160]

Answer:

P1V1= P2V2

Explanation:

Inverse relationship

V2 = V1 X P1/P2

V2= 14.3 L x 45.0 mm Hg/63.0 mmHg= 8.99

8 0
3 years ago
In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
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