Answer:
The person is on the Moon having a weight of 500 N. The acceleration of gravity on the Moon is approximately 1.6 m/s2. What is your his, which includes his space suit?
f= Force (of gravity)=500N
g=acceleration of gravity=1.6m/s^2
m=mass=312kg
m=f/a= 500N/1.6 m/s^2 = 500 (kg-m/1.6m/s^2) = 500/1.6kg = 312kg
his mass is 312kg
Answer:
4.3 m/sec
Explanation:
Here height of cliff = y = 37.6 m
Gravitational acceleration = g = 9.8 m/sec2
vi = 0 m/s
Let's find the time which the diver will take if jumps from there!
Using formula
y = vit+1/2gt2
==> 37.6= 0 + 0.5 ×9.8×
==>= 
==> t = 2.8 sec
In this time the diver has to cover a horizontal distance of 12.12 m
If x = 12.12 m is the horizontal distance to be covered then using
x= Vx × t
==> Vx = x/t
==> Vx= 12.12/2.8 = 4.3 m/s
There’s many terms to it
1 : to keep in a safe or sound state He conserved his inheritance. especially : to avoid wasteful or destructive use of conserve natural resources conserve our wildlife. 2 : to preserve with sugar. 3 : to maintain (a quantity) constant during a process of chemical, physical, or evolutionary change conserved DNA ...
Answer:
60m
Explanation:
According to one of the equation of motions, v² = u²+2as where;
S is the distance
u is the initial velocity
v is the final velocity
a is the acceleration
Since the arrow is shot upwards, the body will experience a negative acceleration due to gravity i.e a = -g
Therefore our equation will become;
v² = u² - 2gS
Given u = 40m/s, g = 10m/s², S = 75m
Substituting to get the final velocity of the arrow we will have;
v² = 40²-2(10)(75)
v² = 1600 - 1500
v² = 100
v = √100
v = 10m/s
Total distance traveled is speed of the object × time taken
Total distance traveled = 10 × 6
= 60m
The arrow has therefore traveled 60m after 6seconds
<span>Density can be calculated and found by dividing the sample's mass by its volume. D=m/v</span>
