Answer:
im not sure go with the first
Explanation:
Answer:
0.492 lb/in^3
Explanation:
From Density of Mercury (13.6g/cm3) given,
Mass = 13.6g
Volume = 1cm3
Now we covert these variables as follows :
For Mass:
454 g = 1 lb
13.6g = 13.6/454 = 0.03lb
For volume:
2.54 cm = 1 in
1cm = 1/2.54 = 0.394in
Volume = (0.394in)^3 = 0.061 in^3
Density = Mass /volume
Density = 0.03lb/0.061 in^3
Density = 0.492 lb/in^3
Answer:
Carbon
Explanation:
Bc i got this question on my test
Answer: The pressure exerted by the
gas, in atm is 1.092
Explanation:
According to the ideal gas equation:'
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
P = Pressure of the gas = ?
V= Volume of the gas
T= Temperature of the gas =
(0°C = 273 K)
n= moles of gas = ![\frac{\text {given mass}}{\text {Molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7BMolar%20mass%7D%7D)
R= Value of gas constant = 0.0821 Latm/K mol
as ![Density=\frac{mass}{Volume}](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7Bmass%7D%7BVolume%7D)
where d is density
![P=\frac{1.983g/L\times 0.0821Latm/Kmol\times 295.165K}{44g/mol}=1.092atm](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1.983g%2FL%5Ctimes%200.0821Latm%2FKmol%5Ctimes%20295.165K%7D%7B44g%2Fmol%7D%3D1.092atm)
Thus pressure exerted by the
gas, in atm is 1.092