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ZanzabumX [31]
2 years ago
5

9a driver has a reaction time of 0.50 s , and the maximum deceleration of her car is 6.0 m/s2 . she is driving at 20 m/s when su

ddenly she sees an obstacle in the road 50 m in front of her.
Physics
1 answer:
dolphi86 [110]2 years ago
7 0
The distance traveled during the reaction time is
d₁ == (20 m/s)*(0.50 s) = 10 m

The deceleration is  6.0 m/s²
The distance, d₂, traveled until the car comes to a complete stop is given by
(20 m/s)²  - 2*(6.0 m/s²)*(d₂ m) = 0
d₂ = 400/12 = 33.333 m

The total distance traveled before the car comes to rest is
d₁ + d₂ = 10 + 33.333 = 43.333 m
Because 43.333 m is less than 50 m, the car will not hit the object.

Answer:
The car comes to a stop before reaching the object. It will not hit the object.

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3 years ago
Describe a situation in which an object's speed is constant but its velocity is changing.
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Historically, use of fossil fuels has lead to all of the following except:
kicyunya [14]

Use of fossil fuels has not lead to increased use of wood as heat source.

Answer: Option D

<u>Explanation:</u>

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Thus, before the introduction of fossil fuels, wood is used as the igniting source for heat energy. But the entry of fossil fuels have reduced the use of wood as igniting source in cooking, burning etc.

Thus, the use of fossil fuels have increased exchange of culture and ideas as fuels are mostly imported from other nations, it lead to development of faster transportation methods and increased the availability of products including heat, plastics and medicine. But similarly, the use of fossil fuels have not increased the use of wood as heat source, instead it decreased the use of wood as heat source.

6 0
3 years ago
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If you place 48 cm object 15 m in front of a convex mirror of focal length 5 m, what is the magnification of the image?
Arisa [49]

Answer:

m = 0.25

Explanation:

Given that,

Object distance, u = -15cm

Height of the object, h = 48

Focal length, f = cm

We need to find the magnification of the image.

Let v is the image distance. Using mirror's equation.

\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}-\dfrac{1}{u}\\\\=\dfrac{1}{5}-\dfrac{1}{(-15)}\\\\=3.75\ cm

Magnification,

m=\dfrac{-v}{u}\\\\=\dfrac{-3.75}{-15}\\\\=0.25

Hence, the magnification of the image is 0.25.

7 0
3 years ago
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