The distance traveled during the reaction time is d₁ == (20 m/s)*(0.50 s) = 10 m
The deceleration is 6.0 m/s² The distance, d₂, traveled until the car comes to a complete stop is given by (20 m/s)² - 2*(6.0 m/s²)*(d₂ m) = 0 d₂ = 400/12 = 33.333 m
The total distance traveled before the car comes to rest is d₁ + d₂ = 10 + 33.333 = 43.333 m Because 43.333 m is less than 50 m, the car will not hit the object.
Answer: The car comes to a stop before reaching the object. It will not hit the object.
for every two sexully producing fish there is one offspring. but for every one asexuall producing fish there is one offspring. so if the asexual fish prodececes more than there will be more than the sexually producing fish.
