Answer:
Tires.
Explanation:
There are the few steps which are discussed below should be taken to increase or extend the life of tires.
(1) Avoid fast starts: Fast start of the vehicle will increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(2) Avoid fast stop: Fast stop of the vehicle will also increase the pressure on the tires due to the friction between the tires and the road will decrease the life of tires.
(3) Avoid sharp turns: The alignment of the wheels and tires are in such a way that they work properly when vehicle is drive in a straight path but sharp turn will increase the uneven pressure on the tires will lead to decrease the life of tires.
Therefore, the life of tires can be extend by avoiding all the above mention actions such as fast stop, start and sharp turns.
Given the following choices;
A) less than your true weight, mg.
B) equal to your true weight, mg.
C) more than your true weight, mg.
D) could be more or less than your true weight, mg, depending on the value of the speed.
The answer is; C
This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.
Answer:
A)
B)
C)
Explanation:
Given that:
- no. of turns i the coil,
- area of the coil,
- time interval of rotation,
- intensity of magnetic field,
(A)
Initially the coil area is perpendicular to the magnetic field.
So, magnetic flux is given as:
..................................(1)
is the angle between the area vector and the magnetic field lines. Area vector is always perpendicular to the area given. In this case area vector is parallel to the magnetic field.
(B)
In this case the plane area is parallel to the magnetic field i.e. the area vector is perpendicular to the magnetic field.
∴ 
From eq. (1)
(C)
According to the Faraday's Law we have:
False the North Star never changes it position
Answer:
Explanation:
Given
mass of sled =26 kg
coefficient of static friction 
coefficient of kinetic friction 
In order to move sled from rest we need to provide a force greater than static friction which is given by
After Moving Sled kinetic friction comes in to play which is less than static friction
therefore minimum force to keep moving sledge at constant velocity is 18.34 N
