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Dmitriy789 [7]
2 years ago
10

If a 1 kg book has 46 Joules of gravitational potential energy how high is the shelf it is on?

Physics
1 answer:
Mashcka [7]2 years ago
4 0

Answer:

4.7m

Explanation:

Given parameters:

Mass of the book  = 1kg

Gravitational potential energy  = 46J

Unknown:

Height of the shelf  = ?

Solution:

The potential energy is due to the position of a body above the ground.

        Gravitational potential energy  = mgh

m is the mass,

g is the acceleration due gravity  = 9.8m/s²

h is the height which is unknown

                       46  = 1 x 9.8 x h

                       h  = 4.7m

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A test charge of 13 mC is at a point P where an external electric field is directed to the right and has a magnitude of 4 3 106
LenKa [72]

Answer:

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C, but the direction is still to the right.

Explanation:

From coulomb's law, F = Eq

Thus,

F = E₁q₁

F = E₂q₂

Then

E₂q₂ = E₁q₁

E_2 = \frac{E_1q_1}{q_2}

where;

E₂ is the external electric field due to second test charge = ?

E₁ is the external electric field due to first test charge = 4 x 10⁶ N/C

q₁ is the first test charge = 13 mC

q₂ is the second test charge = 23 mC

Substitute in these values in the equation above and calculate E₂.

E_2 = \frac{4*10^6*13}{23} = 2.26 *10^6 \ N/C

The magnitude of the external electric field at P will reduce to 2.26 x 10⁶ N/C when 13 mC test charge is replaced with another test charge of 23 mC.

However, the direction of the external field is still to the right.

8 0
3 years ago
A SMA wire in the un-stretched condition is then given an initial strain of εo (to preload the wire) at room temperature (RT). I
julia-pushkina [17]

Answer: tensional force

Explanation:

Tension force on a material occurs when two equal forces act on a material in an opposite direction away from the ends of the material.

Pre-tensing a wire material increases its load bearing capacity and reduces its flexure.

6 0
3 years ago
The force that attracts earth to an object is equal to and opposite the force that earth exerts on the object. Explain why earth
alexandr402 [8]

Answer:

Because of heavy mass

Explanation:

When force acts on a body it tends to accelerate the body. The acceleration produced in the body depends on two things:

1). Magnitude of force

2). Mass of the body

F= ma

⇒ a = F/m  

As the force exerted on earth and another object are the equal in magnitude but opposite in direction. This forces will accelerate the object toward the earth but can't accelerate the earth as earth has very high mass.

a = F/m

This force tends to accelerate the earth but but due to earth's inertia the earth does not accelerate.

7 0
2 years ago
1. One of the timing devices Galileo used was his pulse. Drop a rubber ball from a height of
Kamila [148]

The number of pulse beats elapsed before the rubber ball hits the ground can be obtained when you carry out the experiment yourself. However, the pulse beat method of timing used by Galileo is not reliable because it varies from time to time.

Galileo was interested in studying how objects fall. His discovery was that all objects had the same acceleration irrespective of their mass. This observation was in direct contrast to Aristotle's assertion that the velocity of objects is proportional to their mass.

However, he used his pulse beats as timer during the experiment. This method is unreliable because the pulse beats of a person changes depending on the person's state of mind. A stop clock could have been a more reliable timer than pulse beats.

Learn more: brainly.com/question/7201885

7 0
3 years ago
How many photons strike the cd surface during the playing of a cd 69 minutes in length?
Reptile [31]

Answer:

Photons strike the CD n=1.624 x10^{18}

Explanation:

First of all, it is necessary to calculate the energy produced by a semiconductor laser for 69 minutes:

69minutes*\frac{60s}{1 minute}=4140s

E=0.1x10^{-3}w*4140s=0.414J

Next, it is possible to calculate the number of photons striking the CD surface during this time:

E=\frac{n*h*c}{l}

l=780x10^{-9}m long in CD

c=3x10^8 m/s light velocity

h=6.626x10^{-34} J*s

Solve to n'

n=\frac{E*l}{c*h}=\frac{0.414 J*780x10^{-9}m}{3x10^8m/s*6.626x10^{-34}}

n=1.624 x10^{18}

8 0
3 years ago
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