The work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻² would be
<h3>What is work done?</h3>
The total amount of energy transferred when a force is applied to move an object through some distance.
The work done is the multiplication of applied force with displacement.
Work Done = Force × Displacement
As given in the problem we have to find the work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻²,
Lets us first calculate the displacement of the elevator in 2 seconds if it is accelerating upwards from rest at a rate of 2 ms⁻².
s = ut + 0.5at²
= 0 + 0.5×2×2²
= 4 meters
The work done on the elevator = mgh
=50×9.81×4
=1962 joules
Thus, the work done on the elevator would be 1962 joules.
To learn more about work done, refer to the link;
brainly.com/question/13662169
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