Find the work done on a 50 Kg student by the elevator in 2 seconds, if the elevator is :

1 answer:

5 0

The work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻² would be

The total amount of energy transferred when a force is applied to move an object through some distance.

The work done is the multiplication of applied force with displacement.

Work Done = Force × Displacement

As given in the problem we have to find the work done on a 50 Kg student by the elevator in 2 seconds if the elevator is accelerating upwards from rest at a rate of 2 ms⁻²,

Lets us first calculate the displacement of the elevator in 2 seconds if it is accelerating upwards from rest at a rate of 2 ms⁻².

s = ut + 0.5at²

= 0 + 0.5×2×2²

= 4 meters

The work done on the elevator = mgh

=50×9.81×4

=1962 joules

Thus, the work done on the elevator would be 1962 joules.

To learn more about work done, refer to the link;

brainly.com/question/13662169

#SPJ1

You might be interested in

A light spring obeys Hooke's law. The spring's unstretched length is 34.0 cm. One end of the spring is attached to the top of a

sleet_krkn [62]

When the spring is extended by 44.5 cm - 34.0 cm = 10.5 cm = 0.105 m, it exerts a restoring force with magnitude R such that the net force on the mass is

∑ F = R - mg = 0

where mg = weight of the mass = (7.00 kg) g = 68.6 N.

It follows that R = 68.6 N, and by Hooke's law, the spring constant is k such that

k (0.105 m) = 68.6 N ⇒ k = (68.6 N) / (0.105 m) ≈ 653 N/m

5 0

2 years ago

Which factor affects the angle of sunlight on Earth? The distance between Earth and the sun Earth's tilt from its axis The path

Rainbow [258]

Earth’s tilt from its axis.
For explanation:
The angle in which Earth is at is 23.5°. This causes its tilt which affects how the Sun’s light hits Earth