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Sergeu [11.5K]
1 year ago
3

Which describes what a velocity/time graph would look like with no acceleration?

Chemistry
2 answers:
11111nata11111 [884]1 year ago
4 0

A velocity/time graph would look like with no acceleration is the straight line with zero slope

Here the given data is related with the concept and fundamental of velocity/time graph and the graphical representation where the velocity of an object is concluded with respect to the time is known as velocity-time graph

  • Velocity-time graph refer the information about acceleration where the velocity should be at y-axis and on the other hand the time should be at x-axis
  • And if there is zero acceleration the slope should be shown in horizontal line and when the acceleration is negative there is downward sloping

Therefore the given case in the graph is straight line with zero slope means no acceleration

Know more about velocity/time graph

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EastWind [94]1 year ago
3 0

Answer:

C

Explanation:

got it right

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Natural dyes, although pure from chemicals, are often times more expensive than chemical dyes.

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Who was one of the first scientists to realize the effects of CO2 in the atmosphere?
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<u>Who: </u>Svante Arrhenius.

When: Claimed in 1896 that fossil fuels has a negative effect on our atmosphere.

<u>How:</u> Svante Arrhenius proved that fossil fuels had a negative effect by calculating the output of buildings that emit fossil fuels, and lead to the conclusion by his calculations that the industry might one day bring global warming. Svante Arrhenius' theory of electrolytic dissociation and his model of the greenhouse effect also helped him to prove that his remarks about fossil fuels and global warming is true.

<u>Where:</u>

I cannot find any source that mentions the where. What do you mean by where?

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Which best describes the purpose of bar graphs?
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A bicycle pump contains 250 mL of air at a pressure of 102 kPa. If the pump is
CaHeK987 [17]

Considering the Boyle's law, the new volume becomes 1,148,344.444 mL or 1148.34 L.

<h3>Boyle's law</h3>

Boyle's law relates pressure and volume, stating that the volume occupied by a given mass of gas at constant temperature is inversely proportional to pressure. This means that if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.

Boyle's law is expressed mathematically as:

P×V=k

Now it is possible to assume that you have a certain volume of gas V1 which is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and the following is true:

P1×V1=P2×V2

<h3>New volume</h3>

In this case, you know:

  • P1= 102 kPa= 10335.1 atm (being 1 kPa= 101.325 atm)
  • V1= 250 mL
  • P2= 2.25 atm
  • V2= ?

Replacing in the Boyle's law:

10335.1 atm ×250 mL= 2.25 atm×V2

Solving:

(10335.1 atm ×250 mL)÷ 2.25 atm= V2

<u><em>1,148,344.444 mL= 1148.34 L=  V2</em></u>

Finally, the new volume becomes 1,148,344.444 mL or 1148.34 L.

Learn more about Boyle's law:

brainly.com/question/4147359

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2 years ago
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